<?xml version="1.0" encoding="UTF-8"?>
<rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:dc="http://purl.org/dc/elements/1.1/">
  <channel>
    <title>DEV Community: Amit Upadhyay</title>
    <description>The latest articles on DEV Community by Amit Upadhyay (@amitupadhyay-ai).</description>
    <link>https://dev.to/amitupadhyay-ai</link>
    <image>
      <url>https://media2.dev.to/dynamic/image/width=90,height=90,fit=cover,gravity=auto,format=auto/https:%2F%2Fdev-to-uploads.s3.us-east-2.amazonaws.com%2Fuploads%2Fuser%2Fprofile_image%2F964168%2Faabc77d8-f761-4904-94e2-9ec90091fcd8.png</url>
      <title>DEV Community: Amit Upadhyay</title>
      <link>https://dev.to/amitupadhyay-ai</link>
    </image>
    <atom:link rel="self" type="application/rss+xml" href="https://dev.to/feed/amitupadhyay-ai"/>
    <language>en</language>
    <item>
      <title>How visual Python learning helps students understand algorithms faster</title>
      <dc:creator>Amit Upadhyay</dc:creator>
      <pubDate>Mon, 29 Jun 2026 09:06:09 +0000</pubDate>
      <link>https://dev.to/amitupadhyay-ai/how-visual-python-learning-helps-students-understand-algorithms-faster-ml2</link>
      <guid>https://dev.to/amitupadhyay-ai/how-visual-python-learning-helps-students-understand-algorithms-faster-ml2</guid>
      <description>&lt;h2&gt;
  
  
  How visual Python learning can make algorithms feel less scary
&lt;/h2&gt;

&lt;p&gt;I’ve always felt that algorithms become harder than they need to be when they are explained only in text.&lt;/p&gt;

&lt;p&gt;A student can read the same sorting logic a few times and still not really &lt;em&gt;see&lt;/em&gt; what is happening. The idea sounds simple on paper, but once variables start changing and loops begin nesting, things can get confusing very quickly.&lt;/p&gt;

&lt;p&gt;That is one reason I started thinking more seriously about visual learning.&lt;/p&gt;

&lt;h2&gt;
  
  
  Why algorithms feel difficult
&lt;/h2&gt;

&lt;p&gt;When people learn Python, they usually get one of two experiences. Either they see a wall of code, or they see a simplified animation that looks nice but does not really teach much.&lt;/p&gt;

&lt;p&gt;What many students actually need is something in between. They need a way to watch the code move step by step, while still staying close to the real logic.&lt;/p&gt;

&lt;p&gt;That is what makes this kind of learning useful. It turns something abstract into something you can follow.&lt;/p&gt;

&lt;h2&gt;
  
  
  Why visual learning helps
&lt;/h2&gt;

&lt;p&gt;I’ve noticed that once you can actually see the steps, a lot of the confusion starts to disappear.&lt;/p&gt;

&lt;p&gt;Things like loops, comparisons, recursion, and data structure changes stop feeling like magic tricks. They start feeling more understandable. Not instantly easy, but at least clear enough to build confidence.&lt;/p&gt;

&lt;p&gt;That matters because confidence is a big part of learning algorithms. If a student feels lost too early, they often stop before the idea has a chance to click.&lt;/p&gt;

&lt;h2&gt;
  
  
  The idea behind PyAnimate
&lt;/h2&gt;

&lt;p&gt;PyAnimate was built around that simple idea: help people learn Python by seeing it unfold in motion.&lt;/p&gt;

&lt;p&gt;It blends a browser playground, visual execution, guided prompts, and level-based learning tracks. In practice, that means learners can write Python, watch the execution step by step, and explore algorithm behavior in a way that feels more interactive than reading static explanations.&lt;/p&gt;

&lt;p&gt;It is not meant to be flashy for the sake of it. The goal is to make learning feel more natural, especially for students who understand better when they can &lt;em&gt;see&lt;/em&gt; how something works.&lt;/p&gt;

&lt;h2&gt;
  
  
  Why this matters for students
&lt;/h2&gt;

&lt;p&gt;This approach can help a few different kinds of learners.&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Beginners who are just getting comfortable with Python.&lt;/li&gt;
&lt;li&gt;Students who are learning algorithms for the first time.&lt;/li&gt;
&lt;li&gt;Learners who keep forgetting what an algorithm actually does after reading it.&lt;/li&gt;
&lt;li&gt;People who want a more hands-on way to build intuition.&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;For these learners, animation is not a gimmick. It is a bridge between code and understanding.&lt;/p&gt;

&lt;h2&gt;
  
  
  A simple example
&lt;/h2&gt;

&lt;p&gt;Think about a sorting algorithm.&lt;/p&gt;

&lt;p&gt;If you only read the code, you may understand the structure of the solution. But if you can watch the elements move, compare, and swap step by step, the logic becomes much easier to remember.&lt;/p&gt;

&lt;p&gt;That is the kind of learning experience PyAnimate is trying to support.&lt;/p&gt;

&lt;h2&gt;
  
  
  Final thought
&lt;/h2&gt;

&lt;p&gt;Not every topic needs animation. But for Python algorithms, visual learning can make a real difference.&lt;/p&gt;

&lt;p&gt;It helps students move from “I have seen this code” to “I actually understand how it works.” And in learning, that shift matters a lot.&lt;/p&gt;

&lt;p&gt;That is the direction behind PyAnimate: a calmer, clearer way to learn Python, one step at a time.&lt;/p&gt;

&lt;p&gt;&lt;a href="https://pyanimate.com" rel="noopener noreferrer"&gt;PyAnimate&lt;/a&gt;&lt;/p&gt;

</description>
      <category>algorithms</category>
      <category>beginners</category>
      <category>learning</category>
      <category>python</category>
    </item>
    <item>
      <title>Guṇakasamuccayaḥ — The factors of the sum is the sum of the factors</title>
      <dc:creator>Amit Upadhyay</dc:creator>
      <pubDate>Mon, 29 Jun 2026 00:00:00 +0000</pubDate>
      <link>https://dev.to/sutraflow/gunakasamuccayah-the-factors-of-the-sum-is-the-sum-of-the-factors-1j24</link>
      <guid>https://dev.to/sutraflow/gunakasamuccayah-the-factors-of-the-sum-is-the-sum-of-the-factors-1j24</guid>
      <description>&lt;p&gt;&lt;a href="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fgunakasamuchyah%2Fopengraph-image" class="article-body-image-wrapper"&gt;&lt;img src="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fgunakasamuchyah%2Fopengraph-image" alt="Guṇakasamuccayaḥ" width="1200" height="630"&gt;&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;गुणकसमुच्चयः&lt;/strong&gt; — &lt;em&gt;Gunakasamuchyah&lt;/em&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;The factors of the sum is the sum of the factors.&lt;/strong&gt; The factors of an expression when evaluated at a value equal the expression's value — use this to verify factorizations.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Why it works:&lt;/strong&gt; If P(x) = (x−a)(x−b), then P(a)=0 and P(b)=0. Evaluating the factors and the original polynomial at any value provides a consistency check on the factorization.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Speed advantage:&lt;/strong&gt; Instant factorization verification vs. polynomial expansion.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Best for&lt;/strong&gt;&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Verifying polynomial factorizations&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;▶ &lt;a href="https://www.sutraflow.app/sutras/gunakasamuchyah" rel="noopener noreferrer"&gt;See the animated lesson, practice drills &amp;amp; proof on SutraFlow →&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;em&gt;Originally published at &lt;a href="https://www.sutraflow.app/sutras/gunakasamuchyah" rel="noopener noreferrer"&gt;https://www.sutraflow.app/sutras/gunakasamuchyah&lt;/a&gt;&lt;/em&gt;&lt;/p&gt;

</description>
      <category>vedicmath</category>
      <category>algebra</category>
      <category>verification</category>
    </item>
    <item>
      <title>Guṇitasamuccayaḥ — The product of the sum is the sum of the products</title>
      <dc:creator>Amit Upadhyay</dc:creator>
      <pubDate>Tue, 23 Jun 2026 00:00:00 +0000</pubDate>
      <link>https://dev.to/sutraflow/gunitasamuccayah-the-product-of-the-sum-is-the-sum-of-the-products-3id</link>
      <guid>https://dev.to/sutraflow/gunitasamuccayah-the-product-of-the-sum-is-the-sum-of-the-products-3id</guid>
      <description>&lt;p&gt;&lt;a href="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fgunitasamuchyah%2Fopengraph-image" class="article-body-image-wrapper"&gt;&lt;img src="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fgunitasamuchyah%2Fopengraph-image" alt="Guṇitasamuccayaḥ" width="1200" height="630"&gt;&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;गुणितसमुच्चयः&lt;/strong&gt; — &lt;em&gt;Gunitasamuchyah&lt;/em&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;The product of the sum is the sum of the products.&lt;/strong&gt; The digit sum of a product equals the digit sum of the product of the individual digit sums — a verification tool.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Why it works:&lt;/strong&gt; Digit root is a homomorphism modulo 9: digitRoot(a×b) = digitRoot(digitRoot(a) × digitRoot(b)). This is because the digit root tracks the number modulo 9.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Speed advantage:&lt;/strong&gt; Instant answer verification in 3 steps vs. recomputing the whole multiplication.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Best for&lt;/strong&gt;&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Verifying multiplication, division, and squaring results&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;▶ &lt;a href="https://www.sutraflow.app/sutras/gunitasamuchyah" rel="noopener noreferrer"&gt;See the animated lesson, practice drills &amp;amp; proof on SutraFlow →&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;em&gt;Originally published at &lt;a href="https://www.sutraflow.app/sutras/gunitasamuchyah" rel="noopener noreferrer"&gt;https://www.sutraflow.app/sutras/gunitasamuchyah&lt;/a&gt;&lt;/em&gt;&lt;/p&gt;

</description>
      <category>vedicmath</category>
      <category>verification</category>
      <category>arithmetic</category>
    </item>
    <item>
      <title>Ekanyūnena Pūrveṇa — By one less than the previous one</title>
      <dc:creator>Amit Upadhyay</dc:creator>
      <pubDate>Wed, 17 Jun 2026 00:00:00 +0000</pubDate>
      <link>https://dev.to/sutraflow/ekanyunena-purvena-by-one-less-than-the-previous-one-o23</link>
      <guid>https://dev.to/sutraflow/ekanyunena-purvena-by-one-less-than-the-previous-one-o23</guid>
      <description>&lt;p&gt;&lt;a href="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fekanyunena-purvena%2Fopengraph-image" class="article-body-image-wrapper"&gt;&lt;img src="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fekanyunena-purvena%2Fopengraph-image" alt="Ekanyūnena Pūrveṇa" width="1200" height="630"&gt;&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;एकन्यूनेन पूर्वेण&lt;/strong&gt; — &lt;em&gt;Ekanyunena Purvena&lt;/em&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;By one less than the previous one.&lt;/strong&gt; Multiply by a string of 9s: subtract 1 from the multiplicand for the left part; find the complement of the multiplicand for the right part.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Why it works:&lt;/strong&gt; n × (10^k − 1) = n × 10^k − n = (n−1) followed by complement(n, k). Because 10^k − n is the complement of n with respect to 10^k: writing n in k digits and subtracting from 10^k gives the right portion.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Speed advantage:&lt;/strong&gt; 1 mental step vs 9+ for multiplying by 9, 99, 999, 9999.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Best for&lt;/strong&gt;&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Multiplying by numbers that are all 9s&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;▶ &lt;a href="https://www.sutraflow.app/sutras/ekanyunena-purvena" rel="noopener noreferrer"&gt;See the animated lesson, practice drills &amp;amp; proof on SutraFlow →&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;em&gt;Originally published at &lt;a href="https://www.sutraflow.app/sutras/ekanyunena-purvena" rel="noopener noreferrer"&gt;https://www.sutraflow.app/sutras/ekanyunena-purvena&lt;/a&gt;&lt;/em&gt;&lt;/p&gt;

</description>
      <category>vedicmath</category>
      <category>multiplication</category>
      <category>specialnumbers</category>
    </item>
    <item>
      <title>Sopāntyadvayamantyam — The ultimate and twice the penultimate</title>
      <dc:creator>Amit Upadhyay</dc:creator>
      <pubDate>Thu, 11 Jun 2026 00:00:00 +0000</pubDate>
      <link>https://dev.to/sutraflow/sopantyadvayamantyam-the-ultimate-and-twice-the-penultimate-3eb7</link>
      <guid>https://dev.to/sutraflow/sopantyadvayamantyam-the-ultimate-and-twice-the-penultimate-3eb7</guid>
      <description>&lt;p&gt;&lt;a href="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fsopaantyadvayamantyam%2Fopengraph-image" class="article-body-image-wrapper"&gt;&lt;img src="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fsopaantyadvayamantyam%2Fopengraph-image" alt="Sopāntyadvayamantyam" width="1200" height="630"&gt;&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;सोपान्त्यद्वयमन्त्यम्&lt;/strong&gt; — &lt;em&gt;Sopaantyadvayamantyam&lt;/em&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;The ultimate and twice the penultimate.&lt;/strong&gt; In certain sum-of-fractions equations, the answer combines the last and second-to-last terms in a specific ratio.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Why it works:&lt;/strong&gt; For equations of the form 1/(a×b) + 1/(b×c) + ... + 1/(x×y) = result, the Vedic pattern recognizes the telescoping nature and the role of the last pair.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Speed advantage:&lt;/strong&gt; Direct pattern application vs. full fraction addition.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Best for&lt;/strong&gt;&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Special fraction equations&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;▶ &lt;a href="https://www.sutraflow.app/sutras/sopaantyadvayamantyam" rel="noopener noreferrer"&gt;See the animated lesson, practice drills &amp;amp; proof on SutraFlow →&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;em&gt;Originally published at &lt;a href="https://www.sutraflow.app/sutras/sopaantyadvayamantyam" rel="noopener noreferrer"&gt;https://www.sutraflow.app/sutras/sopaantyadvayamantyam&lt;/a&gt;&lt;/em&gt;&lt;/p&gt;

</description>
      <category>vedicmath</category>
      <category>fractions</category>
      <category>algebra</category>
    </item>
    <item>
      <title>Śeṣāṇyaṅkena Caramaṇa — The remainders by the last digit</title>
      <dc:creator>Amit Upadhyay</dc:creator>
      <pubDate>Fri, 05 Jun 2026 00:00:00 +0000</pubDate>
      <link>https://dev.to/sutraflow/sesanyankena-caramana-the-remainders-by-the-last-digit-4268</link>
      <guid>https://dev.to/sutraflow/sesanyankena-caramana-the-remainders-by-the-last-digit-4268</guid>
      <description>&lt;p&gt;&lt;a href="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fshesanyankena-charamena%2Fopengraph-image" class="article-body-image-wrapper"&gt;&lt;img src="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fshesanyankena-charamena%2Fopengraph-image" alt="Śeṣāṇyaṅkena Caramaṇa" width="1200" height="630"&gt;&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;शेषाण्यङ्केन चरमेण&lt;/strong&gt; — &lt;em&gt;Shesanyankena Charamena&lt;/em&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;The remainders by the last digit.&lt;/strong&gt; Express numbers in terms of a reference base and use remainders (vinculum) to simplify complex calculations.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Why it works:&lt;/strong&gt; Vinculum representation: replace digits &amp;gt; 5 with (digit−10) and carry +1 forward. This converts digits to a 'balanced' ±5 range, reducing carry complexity in subsequent operations.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Speed advantage:&lt;/strong&gt; Reduces mental load in large multiplication/division by keeping digits small.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Best for&lt;/strong&gt;&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Simplifying numbers with large digits (6–9) for computation&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;▶ &lt;a href="https://www.sutraflow.app/sutras/shesanyankena-charamena" rel="noopener noreferrer"&gt;See the animated lesson, practice drills &amp;amp; proof on SutraFlow →&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;em&gt;Originally published at &lt;a href="https://www.sutraflow.app/sutras/shesanyankena-charamena" rel="noopener noreferrer"&gt;https://www.sutraflow.app/sutras/shesanyankena-charamena&lt;/a&gt;&lt;/em&gt;&lt;/p&gt;

</description>
      <category>vedicmath</category>
      <category>numbersystem</category>
      <category>arithmetic</category>
    </item>
    <item>
      <title>Vyaṣṭisamaṣṭhi — Part and whole</title>
      <dc:creator>Amit Upadhyay</dc:creator>
      <pubDate>Sat, 30 May 2026 00:00:00 +0000</pubDate>
      <link>https://dev.to/sutraflow/vyastisamasthi-part-and-whole-1nn9</link>
      <guid>https://dev.to/sutraflow/vyastisamasthi-part-and-whole-1nn9</guid>
      <description>&lt;p&gt;&lt;a href="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fvyashtisamasthi%2Fopengraph-image" class="article-body-image-wrapper"&gt;&lt;img src="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fvyashtisamasthi%2Fopengraph-image" alt="Vyaṣṭisamaṣṭhi" width="1200" height="630"&gt;&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;व्यष्टिसमष्टि&lt;/strong&gt; — &lt;em&gt;Vyashtisamasthi&lt;/em&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Part and whole.&lt;/strong&gt; Factor a quadratic by finding two numbers whose sum is the middle coefficient and product is the last — the Vedic way to factor trinomials.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Why it works:&lt;/strong&gt; x²+(a+b)x+ab = (x+a)(x+b). The sutra recognizes that the 'individual' factors (vyashti) combine into the 'whole' (samasthi) through their sum and product.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Speed advantage:&lt;/strong&gt; Structured search replaces random trial-and-error.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Best for&lt;/strong&gt;&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Factoring quadratic and higher-degree polynomials&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;▶ &lt;a href="https://www.sutraflow.app/sutras/vyashtisamasthi" rel="noopener noreferrer"&gt;See the animated lesson, practice drills &amp;amp; proof on SutraFlow →&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;em&gt;Originally published at &lt;a href="https://www.sutraflow.app/sutras/vyashtisamasthi" rel="noopener noreferrer"&gt;https://www.sutraflow.app/sutras/vyashtisamasthi&lt;/a&gt;&lt;/em&gt;&lt;/p&gt;

</description>
      <category>vedicmath</category>
      <category>algebra</category>
      <category>factorization</category>
    </item>
    <item>
      <title>Yāvadūnaṃ — Whatever the deficiency</title>
      <dc:creator>Amit Upadhyay</dc:creator>
      <pubDate>Sun, 24 May 2026 00:00:00 +0000</pubDate>
      <link>https://dev.to/sutraflow/yavadunam-whatever-the-deficiency-5a98</link>
      <guid>https://dev.to/sutraflow/yavadunam-whatever-the-deficiency-5a98</guid>
      <description>&lt;p&gt;&lt;a href="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fyaavadunam%2Fopengraph-image" class="article-body-image-wrapper"&gt;&lt;img src="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fyaavadunam%2Fopengraph-image" alt="Yāvadūnaṃ" width="1200" height="630"&gt;&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;यावदूनम्&lt;/strong&gt; — &lt;em&gt;Yaavadunam&lt;/em&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Whatever the deficiency.&lt;/strong&gt; Square a number near a base: subtract (or add) the deficiency to get the left part, square the deficiency for the right part.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Why it works:&lt;/strong&gt; For n near base B with deficiency d (n = B−d): n² = (B−d)² = B²−2Bd+d² = B(B−2d)+d² = B(n−d)+d². Left part = n−d = B−2d; right part = d². Above base: n = B+d → n² = B(n+d)+d².&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Speed advantage:&lt;/strong&gt; 2 mental steps vs 8+ for squaring numbers near a base.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Best for&lt;/strong&gt;&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Squaring numbers near powers of 10&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;▶ &lt;a href="https://www.sutraflow.app/sutras/yaavadunam" rel="noopener noreferrer"&gt;See the animated lesson, practice drills &amp;amp; proof on SutraFlow →&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;em&gt;Originally published at &lt;a href="https://www.sutraflow.app/sutras/yaavadunam" rel="noopener noreferrer"&gt;https://www.sutraflow.app/sutras/yaavadunam&lt;/a&gt;&lt;/em&gt;&lt;/p&gt;

</description>
      <category>vedicmath</category>
      <category>squaring</category>
      <category>nearbase</category>
    </item>
    <item>
      <title>Calanā-Kalanābhyāṃ — Differences and similarities</title>
      <dc:creator>Amit Upadhyay</dc:creator>
      <pubDate>Mon, 18 May 2026 00:00:00 +0000</pubDate>
      <link>https://dev.to/sutraflow/calana-kalanabhyam-differences-and-similarities-464b</link>
      <guid>https://dev.to/sutraflow/calana-kalanabhyam-differences-and-similarities-464b</guid>
      <description>&lt;p&gt;&lt;a href="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fchalana-kalanabyham%2Fopengraph-image" class="article-body-image-wrapper"&gt;&lt;img src="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fchalana-kalanabyham%2Fopengraph-image" alt="Calanā-Kalanābhyāṃ" width="1200" height="630"&gt;&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;चलन-कलनाभ्याम्&lt;/strong&gt; — &lt;em&gt;Chalana-Kalanabyham&lt;/em&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Differences and similarities.&lt;/strong&gt; Use calculus-like derivative thinking: find roots of a polynomial by examining its rate of change pattern.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Why it works:&lt;/strong&gt; Related to finding equal/repeated roots using differential calculus patterns. If P(x) and P'(x) share a root, that root is repeated. Vedic method formalizes spotting these patterns without formal calculus.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Speed advantage:&lt;/strong&gt; Identifies repeated roots and special factorizations rapidly.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Best for&lt;/strong&gt;&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Advanced polynomial analysis&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;▶ &lt;a href="https://www.sutraflow.app/sutras/chalana-kalanabyham" rel="noopener noreferrer"&gt;See the animated lesson, practice drills &amp;amp; proof on SutraFlow →&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;em&gt;Originally published at &lt;a href="https://www.sutraflow.app/sutras/chalana-kalanabyham" rel="noopener noreferrer"&gt;https://www.sutraflow.app/sutras/chalana-kalanabyham&lt;/a&gt;&lt;/em&gt;&lt;/p&gt;

</description>
      <category>vedicmath</category>
      <category>algebra</category>
      <category>calculusadjacent</category>
    </item>
    <item>
      <title>Pūraṇāpūraṇābhyāṃ — By the completion or non-completion</title>
      <dc:creator>Amit Upadhyay</dc:creator>
      <pubDate>Wed, 13 May 2026 00:00:00 +0000</pubDate>
      <link>https://dev.to/sutraflow/puranapuranabhyam-by-the-completion-or-non-completion-lkp</link>
      <guid>https://dev.to/sutraflow/puranapuranabhyam-by-the-completion-or-non-completion-lkp</guid>
      <description>&lt;p&gt;&lt;a href="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fpuranapuranabhyam%2Fopengraph-image" class="article-body-image-wrapper"&gt;&lt;img src="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fpuranapuranabhyam%2Fopengraph-image" alt="Pūraṇāpūraṇābhyāṃ" width="1200" height="630"&gt;&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;पूरणापूरणाभ्याम्&lt;/strong&gt; — &lt;em&gt;Puranapuranabhyam&lt;/em&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;By the completion or non-completion.&lt;/strong&gt; Complete the square (or cube) by adding and subtracting the missing term — Vedic style completion method.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Why it works:&lt;/strong&gt; To solve x²+bx=c: recognize b/2, add (b/2)² to both sides → (x+b/2)²=c+(b/2)². Vedic framing sees this as 'completing what is missing to make a perfect square'.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Speed advantage:&lt;/strong&gt; Direct insight into root structure without memorizing quadratic formula.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Best for&lt;/strong&gt;&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Quadratic equations, completing the square&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;▶ &lt;a href="https://www.sutraflow.app/sutras/puranapuranabhyam" rel="noopener noreferrer"&gt;See the animated lesson, practice drills &amp;amp; proof on SutraFlow →&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;em&gt;Originally published at &lt;a href="https://www.sutraflow.app/sutras/puranapuranabhyam" rel="noopener noreferrer"&gt;https://www.sutraflow.app/sutras/puranapuranabhyam&lt;/a&gt;&lt;/em&gt;&lt;/p&gt;

</description>
      <category>vedicmath</category>
      <category>algebra</category>
      <category>quadratics</category>
    </item>
    <item>
      <title>Saṅkalana-vyavakalanābhyāṃ — By addition and subtraction</title>
      <dc:creator>Amit Upadhyay</dc:creator>
      <pubDate>Thu, 07 May 2026 00:00:00 +0000</pubDate>
      <link>https://dev.to/sutraflow/sankalana-vyavakalanabhyam-by-addition-and-subtraction-8g5</link>
      <guid>https://dev.to/sutraflow/sankalana-vyavakalanabhyam-by-addition-and-subtraction-8g5</guid>
      <description>&lt;p&gt;&lt;a href="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fsankalana-vyavakalanabhyam%2Fopengraph-image" class="article-body-image-wrapper"&gt;&lt;img src="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fsankalana-vyavakalanabhyam%2Fopengraph-image" alt="Saṅkalana-vyavakalanābhyāṃ" width="1200" height="630"&gt;&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;संकलन-व्यवकलनाभ्याम्&lt;/strong&gt; — &lt;em&gt;Sankalana-vyavakalanabhyam&lt;/em&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;By addition and subtraction.&lt;/strong&gt; Add the two equations to get one answer; subtract them to get another. Two equations → two answers in two steps.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Why it works:&lt;/strong&gt; If ax+by=p and bx+ay=q, then adding: (a+b)(x+y)=p+q → x+y=(p+q)/(a+b). Subtracting: (a−b)(x−y)=p−q → x−y=(p−q)/(a−b). Then x and y follow from x=(sum+diff)/2.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Speed advantage:&lt;/strong&gt; Symmetric equations solved in 2 steps instead of 6.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Best for&lt;/strong&gt;&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Symmetric simultaneous equations&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;▶ &lt;a href="https://www.sutraflow.app/sutras/sankalana-vyavakalanabhyam" rel="noopener noreferrer"&gt;See the animated lesson, practice drills &amp;amp; proof on SutraFlow →&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;em&gt;Originally published at &lt;a href="https://www.sutraflow.app/sutras/sankalana-vyavakalanabhyam" rel="noopener noreferrer"&gt;https://www.sutraflow.app/sutras/sankalana-vyavakalanabhyam&lt;/a&gt;&lt;/em&gt;&lt;/p&gt;

</description>
      <category>vedicmath</category>
      <category>algebra</category>
      <category>simultaneousequation</category>
    </item>
    <item>
      <title>Ānurūpye Śūnyamanyat — If one is in ratio, the other is zero</title>
      <dc:creator>Amit Upadhyay</dc:creator>
      <pubDate>Fri, 01 May 2026 00:00:00 +0000</pubDate>
      <link>https://dev.to/sutraflow/anurupye-sunyamanyat-if-one-is-in-ratio-the-other-is-zero-1fm6</link>
      <guid>https://dev.to/sutraflow/anurupye-sunyamanyat-if-one-is-in-ratio-the-other-is-zero-1fm6</guid>
      <description>&lt;p&gt;&lt;a href="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fanurupye-shunyamanyat%2Fopengraph-image" class="article-body-image-wrapper"&gt;&lt;img src="https://media2.dev.to/dynamic/image/width=800%2Cheight=%2Cfit=scale-down%2Cgravity=auto%2Cformat=auto/https%3A%2F%2Fwww.sutraflow.app%2Fsutras%2Fanurupye-shunyamanyat%2Fopengraph-image" alt="Ānurūpye Śūnyamanyat" width="1200" height="630"&gt;&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;आनुरूप्ये शून्यमन्यत्&lt;/strong&gt; — &lt;em&gt;Anurupye Shunyamanyat&lt;/em&gt;&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;If one is in ratio, the other is zero.&lt;/strong&gt; In simultaneous equations, if the ratio of coefficients matches, one variable vanishes and the other solves directly.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Why it works:&lt;/strong&gt; When two equations have coefficients in the same ratio for one variable, subtracting the scaled equations eliminates it. The remaining variable is found in one step.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Speed advantage:&lt;/strong&gt; Proportionality recognition cuts 4 steps to 1.&lt;/p&gt;

&lt;p&gt;&lt;strong&gt;Best for&lt;/strong&gt;&lt;/p&gt;

&lt;ul&gt;
&lt;li&gt;Simultaneous equations with ratio structure&lt;/li&gt;
&lt;/ul&gt;

&lt;p&gt;▶ &lt;a href="https://www.sutraflow.app/sutras/anurupye-shunyamanyat" rel="noopener noreferrer"&gt;See the animated lesson, practice drills &amp;amp; proof on SutraFlow →&lt;/a&gt;&lt;/p&gt;

&lt;p&gt;&lt;em&gt;Originally published at &lt;a href="https://www.sutraflow.app/sutras/anurupye-shunyamanyat" rel="noopener noreferrer"&gt;https://www.sutraflow.app/sutras/anurupye-shunyamanyat&lt;/a&gt;&lt;/em&gt;&lt;/p&gt;

</description>
      <category>vedicmath</category>
      <category>algebra</category>
      <category>simultaneousequation</category>
    </item>
  </channel>
</rss>
