The "Hole" Truth: Understanding JavaScript's Sparse Arrays and Unexpected Behaviors

Blaise Pascal Shyaka — Sun, 12 Jan 2025 15:14:37 +0000

I was recently brushing up on my Data Structures and Algorithms skills, specifically, sorting algorithms; and I found myself in an interesting situation.

How do I create a random array of length n of values to test my sorting algorithm? You might say that's easy, and it truly is. In your head you probably came up with something like this:

function randomArray(n) {
    const arrToReturn = [];

    for (let i = 0; i < n; i++) {
        arrToReturn.push(Math.floor(Math.random() * 10));
    }
    return arrToReturn;
}

This definitely works as intended. But I was looking for something much simpler. Preferably a one-liner. Well, the first thought that came to mind was to use new Array().

const randomArray = (n) => new Array(n).map(() => Math.floor(Math.random() * 10));

console.log(randomArray(5))

What do you expect this to log?

Well, I was expecting this to log an array of random 5 values. If you weren't, then cheers! You know what I'm about to discuss :)

To my surprise, it's not the case. It logs this in Node 20:
[ <5 empty items> ]

Hmmm ... Puzzling!

Interestingly, console.log(randomArray(5).length) logs 5.

So, why does this happen? Well, let's talk about Sparse Arrays in Javascript!

Sparse Arrays

Sparse arrays are arrays containing one or more empty slots. For instance:

new Array(2)
// [<2 empty items>]

[1, , , 3]
// [1, <2 empty items>, 3]

So, how does this work?

Well, when you create an array in JS with new Array(5), it creates an array with 5 uninitialized slots. This means that they do not contain anything; not null, not undefined.

Okay, I get that! But can't you call .map on those "slots"?

Well, when you call iterative methods such as forEach, map, reduce, and filter, etc... on a sparse array, these empty slots are skipped.

Let's take a look at our function randomArray again.

const randomArray = (n) => new Array(n).map(() => Math.floor(Math.random() * 10));

We create an array of length n with new Array(n) which returns a sparse array [<5 empty items>]. Then we call map on that array. Since all the slots are empty, they all skipped. Hence, the result we got!

Why does calling `.length` on a sparse array return a value then?

This is due to the way .length array method is implemented in JS. To get the value of length, we take the largest index and just add 1. And since sparse arrays are indexed, we'll get the length value as expected. You can read more here.

Let's fix our buggy `randomArray` function above

Since sparse arrays contain empty or non-initialized slots, hence, not iterable, we can fix this by filling these slots with some values. We can achieve that by using the .fill array method:

const randomArray = (n) => new Array(n).fill().map(() => Math.floor(Math.random() * 10));

console.log(randomArray(5))

And now, we're good to go!

DEV Community: Blaise Pascal Shyaka

The "Hole" Truth: Understanding JavaScript's Sparse Arrays and Unexpected Behaviors

Sparse Arrays

Why does calling .length on a sparse array return a value then?

Let's fix our buggy randomArray function above

Why does calling `.length` on a sparse array return a value then?

Let's fix our buggy `randomArray` function above