The latest articles on DEV Community by Buddika Abeykoon (@buddika_b). https://dev.to/buddika_b https://media2.dev.to/dynamic/image/width=90,height=90,fit=cover,gravity=auto,format=auto/https:%2F%2Fdev-to-uploads.s3.amazonaws.com%2Fuploads%2Fuser%2Fprofile_image%2F736353%2F3de32c57-efad-413c-8f11-065b211df81c.jpeg https://dev.to/buddika_b en Buddika Abeykoon Fri, 08 May 2026 08:59:06 +0000 https://dev.to/buddika_b/why-float-and-double-outputs-are-different-apo https://dev.to/buddika_b/why-float-and-double-outputs-are-different-apo <div class="highlight js-code-highlight"> <pre class="highlight plaintext"><code>float f = Long.MAX_VALUE; double d = Long.MAX_VALUE; System.out.println("Float max value is : "+ f); System.out.println("Double max value is : "+ d); </code></pre> </div> <p>===============================================<br> Float max value is : 9.223372E18<br> Double max value is : 9.223372036854776E18<br> ===============================================*/</p> <p>When we assign Long.MAX_VALUE to float and double, both try to store a very large number. But float cannot keep many digits accurately, so Java rounds the value and shows a shorter number like 9.223372E18. double has higher precision, so it can store more digits and shows a more accurate value like 9.223372036854776E18. That’s why both outputs are different even though they come from the same value.</p> java softwareengineering softwaredevelopment