DEV Community: NilufarBukhorova

Masala

NilufarBukhorova — Sat, 11 Jun 2022 13:02:11 +0000

N1-->
Ikki nuqta orasidagi masofani hisoblab beradigan funksiya tuzing.

nomi: distance
parametrlari: int aX, int aY, int bX, int bY
qaytarishi: shu ikki nuqta orasidagi masofani float sifatida qaytaradi. Answer:

#include <iostream>
#include <cmath>

using namespace std;

  float distance(int aX, int aY, int bX, int bY)
{
  int a= aY - bY;
  int b= aX - bY;

  int cKvadrat = a*a + b*b;

  int c = sqrt(cKvadrat); //square root

  return c;
  //return sqrt(pow(aY - bY,2)+ pow(aX - bY,2))
}

int main() 
{
  cout << distance(5,6,2,2);
 return 0;
}

N2-->
Berilgan nuqta aylana ichidami yo'qmi aniqlaydigan funksiya tuzing.

nomi: pointIsInCircle
parametrlar:
- aylana markazini anglatuvchi int cX, int cY
- aylana radiusini anglatuvchi int cRadius
- nuqta koordinasini anglatuvchi int pX, int pY
qaytarishi: berilgan nuqta aylana ichida bo'lsa true yo'qsa false qaytaradi.
yuqorida yaratilgan distance funksiyasidan foydalaning.

Answer:

#include <iostream>
#include <cmath>

using namespace std;
float distance(int aX, int aY, int bX, int bY)
{
  int a= aY - bY;
  int b= aX - bY;

  int cKvadrat = a*a + b*b;

  int c = sqrt(cKvadrat); //square root

  return c;
  //return sqrt(pow(aY - bY,2)+ pow(aX - bY,2))
}
bool pointIsInCircle(int cX, int cY, int cRadius, int pX, int pY)
{
  return distance(cX, cY, pX, pY) < cRadius;
}

int main() 
{
  cout << pointIsInCircle(3,3,2,5,5) << endl;
 return 0;
}

Comand: if - else vs else if

NilufarBukhorova — Tue, 10 May 2022 09:39:13 +0000

Odatda if else komandasi ternary komandasini o'rnida bemalol kela oladi. Farqi ternaryda branchlar 2ta bo'lsagina, masalani ishlasa bo'ladi, if komandasi 2 va undan ortiq execution partlar mavjud bo'lgan masalalarni bemalol ishlay oladi.

if komandasida beriladigan ifoda tog'ri bo'lsagina uni chop etadi.

   if( expression )
{
statement1
}

if statementda yo'l qo'yiladigan kichik xatolar

if (expression) shu ifodadan so'ng ; mana bu belgini qo'yish xato hisoblanib, ifoda shu qatorda tugadi degan komadani berib yuboradi.
if ning (expression) qismida = bu belgini bitta qo'yish xato, chunki teng bir o'zi kelganda o'zgaruvchi uchun yangi qiymat o'zlashishida ishlatiladi, ya'ni == shu belgini qo'yish to'g'ri bo'ladi.
- yana bir kichik qoida bor, agarda if, elseda statement, ya'ni buyruq bitta bo'lsa, {} bularni qo'yish shart emas.

if-else

If else bn ko'p hollarda qo'llanadigan qo'shimcha komanda bu else hisoblanib, if dagi ifoda xato bo'lganda ikkinchi statement chiqar degan buyruq berishda ishlatiladi.

if(expression) 
{
statement1
}
else 
{
statement2
}

if else vs else if

Bu ikki komanda aslida bir xil bo'lib, else komandasini ichida bemalol xohlagancha, if else komandasini o'zida foydalansa bo'ladi. Shuni hisobiga aslida if else komandasi else if deb ko'rinadi, ya'ni:

#include <iostream>

 using namespace std;

 int main()
{

int baho;

cin >> baho;

if(baho >= 90)

{

cout << "A" << endl;

}


else


{

if (baho >= 80)

{

cout <<< "B" <<<< endl;

}


else


{

if (baho > 70)

{

cout << "C" << endl;

}

else

{

if (baho > 60)

{

cout << "D" <<<<endl;

}

else


{


cout << "F" << endl;

}

}

}

}

return 0;

42}

1 #include <iostream>

3 using namespace std;


5 int main()
{


int baho;


cin >> baho;

10

if (baho >= 90)

cout << "A" << endl;

else if(baho >= 80)

cout << "B" << endl; 

else if(baho >= 70)

cout << "C" << endl;

else if(baho >= 60)

cout << "D" << endl;

else

cout << "F" << endl;


return 0;
}

C++da Operators

NilufarBukhorova — Sun, 01 May 2022 21:09:01 +0000

Operatorlar ikkiga turga bo'linib, ular quyidagilar:
binary(+,/,*,-)

unary

Arithmetic operators

/ amalini bajarayotganda, ma'lumotni turi muhim bo'lib, kasr son kasr songa, butun son butun songa bo'linayotganini bilish kerak, yo'qsa misolni javobida o'zgarish bo'ladi.
modulus faqat butun sonlar ustida amallarni bajaradi.
amallar matematika bn bir xildek ketma ketlikda bajariladi.
shortcuts
- a += 1
- a *(/, -, %)= 4
- faqat ushbu qiymatlar uchun shortcut mavjud:
- * a += 1* --> a++;
- * a -= 1* --> a--;

Danger

++x --> increase x by 1 and do other operations
x++ --> do other operations and increase by 1
--x --> decrease x by 1 and do other operations
x-- --> do other operations and decrease by 1

sample int x =5; int y =x++;

cout << x << y << endl;

after running, the answer is---> 6 5

Relational operator

relationship between left and right sides
result is always either True(1) or False(0)
operators-- <, <=, ==, >=, >, !=

Logical operators

!=not
&&=and--> hammasi to'g'ri bo'lishi shart.
||=or --> 1tasi to'g'ri bo'lsa ham, hisobga o'taveradi.

C++da Variables and Data types

NilufarBukhorova — Wed, 27 Apr 2022 21:47:07 +0000

Data types

Int :

short, long, int (butun sonlar);

Real number :

float, double (kasr sonlar);

Character :

char (belgilar).

int age=14;
cout << age + 5 * 26 << endl; (144)
age= -15

Declaration

bu o'zgaruvchilarni e'lon qilish;
- int son;

Assignment

bu o'zgaruvchiga qiymat o'zgartirish;
- son=25;

Initalization

o'zgaruvchini e'lon qiish vaqtida birdaniga qiymat berish;
- int boshqason = 16;

o'zgaruvchi nomi harflar, raqamlar va _ belgisidan iborat bo'lishi kerak.

int a=5;
int b=a;
int c=a+b;

int a;
float b; int a,c;
int c; float b,d;
float d;

Garbage value

declaration kiritilsayu, o'zgaruvchi miqdori kiritilmasa councilda chiqadigan taxminiy sonlar

   int a= 123.45 --> 123
   float a= 123 --> 123.00

int vazn = (int)[majburlash] 120.123

int a=10;
int b= a+10;
int c= a+b;int d+ a+b+c;

a=b=c=d=60

cin >>

o'zgaruvchini o'qiydigan komanda

char --> Ascii table

char belgi= 'a'
cout << (char) (belgi/3) << endl; [majburlash]

iomanip

input output manipulation, kutubxona

setw()

o'zgaruvchi uchun print qlishda bo'sh katakchalar so'raydi
- cout << setw(15) << son << endl; [by default right-aligned]
- cout << left << setw (15) << son << endl;

setfill('')

setw() orqali ajratilgan yacheykalarni belgilar bn to'ldiradi.

setprecision

double sonlarda anilashtirish vazifani bajaradi, ya'ni kasr sondagi nuqtadan keyin keluvchi sonlarni ham chiqazib beradi. Faqat nuqtadan keyingisiga ta'sir qiladi.
- 24.16

fixed

setprecision komandasi birgalikda ishlatiladigan komanda bo'lib, uqta jooyida qolsin degan ma'noda keladi.

Terminal komandalar part 3

NilufarBukhorova — Mon, 25 Apr 2022 22:11:33 +0000

`alias nickname=''`

bu komanda takroriy ishlatiladigan komandalar uchun yangi nickname (taxallus) beradi.

`g++ main.cpp -o dastur && ./dastur`

main.cpp nomli faylni compilatsiya qiladi va birdaniga ishga tushiradi.

`nano`

faylni terminalda ochadi

`./..a.out`

birdaniga bitta oldingi papkaga kirib, uning ichidagi ma'lumotni chiqaradi

`include`

kerakli kutubxonani chaqiradi. Masalan "iostream" (input output stream)

`terminal = council`

`std`

standart namespace

`cout`

std::cout, std namespaceni boshqalaridan ajratib turishi uchun ishlatiladi.

`int main()`

dasturga kirish uchun funksiya
int main() siz dastur ishlamaydi.

`return 0`

dastur muvaffaqiyatli bo'lganini aniqlashtirish uchun foydalaniladi.

`"string"`

qo'shtirnoq ichida yozilgan so'z va sonlar "string" deyiladi.

`&&`

komandalarni bir vaqtda birin ketin bajarilishini ta'minlaydi

`// (ctrl+/)`

// c++ dasturida izoh qoldirishda foydalaniladi

`\n`

new line = endl. Sonlar bn ishlamaydi.
\ backslash-- escape characters

Terminal komandalar part 2

NilufarBukhorova — Sat, 23 Apr 2022 07:00:36 +0000

`cd ~`

birdaniga home papkaga o'tadi.

`cd ~/ cpp (any file)`

homeda mavjud bo'lgan cpp filega birdaniga o'tadi.

`_, -, "`

bu belgilar orqali yozilganda, mkdir bn bir nomli papka yasaladi.

`r.m`

remove FILES

`r.m -r`

PAPKAlarni o'chiradi

`open.`

papkani boshqa brauzerda, boshqa joyda ochadi, terminalda emas

`date`

sanani chiqazadi

`date + '%d-%m-%y`

sanani tartibli holda chiqazadi. (23-04-22)

`code.`

code degan dasturda faylni ochadi

`mkdir $ (date + '%d-%m-%y')`

bugungi sana nomi bn papka yaratadi

`g++`

compiler

terminal

NilufarBukhorova — Tue, 19 Apr 2022 12:13:02 +0000

`pwd`

print working directory

`clear`

delete all messages in terminal page

`ls (-a)`

terminaldagi papkalar ro'yhatini chiqarib beradi

`mkdir`

terminalga papka qo'shadi

`cd`

current directoryni o'zgarrtiradi

`cd ..`

shortcut, backspace

`cat`

terminaldagi txt fayllarni terminal ekaraniga chiqazib beradi.

Terminal

NilufarBukhorova — Tue, 19 Apr 2022 11:45:49 +0000

`pwd`

print working directory ## clear
delete all messages in terminal ## ls (-a)
terminaldagi papkalar roýhatini chiqarib beradi ## mkdir
terminalga papka qòshadi ## cd
current directoryni òzgartiradi

Nilufar

NilufarBukhorova — Sat, 16 Apr 2022 12:26:46 +0000

Alphabet of korean language

by Nilufar Bukhorova

Korean language devided into two parts:
- simple letters
- diphthongs All of them are 40. Nowadays it is easy to learn, because as the past. there are not any hieroglyphs. If you have any other questions, please apply this account:

Here

and you can learn this from online videos in youtube