How to update your database through django_rest_framework.

tobiadiks — Tue, 05 Jan 2021 12:11:53 +0000

Last week I came across questions on how to update your database through REST API reason is because most of them faced one issue or the other.

Here is a snippet that works via using a decorator
views.py

from rest_framework.decorator import api_view
from rest_framework.response import Response
from .models import my_model
from .serializer import mySerializer

@api_view(['GET','PUT'])
def updateDb(request, pk):
    try:
        model = my_model.objects.get(pk=pk)
    except:
        return.Response('Not Found')
    if request.method == 'PUT':
        serializer = mySerializer(model, request.data)
        if serializer.is_valid():
            serializer.save()
            return Response ("Updated")
        else:
            return Response ("Failed")
    if request.method == 'GET':
        serializer=mySerializer (models)
        return Response (serializer.data)

Writing an API in Django (Class Based)

tobiadiks — Tue, 05 Jan 2021 08:09:28 +0000

Rest API solve the problem of writing specific codes for different platform.
Django is a Python framework that supports the MVT and follows the DRY principle for writing codes.
To write API for your Django web app, here is how to go about it.

pip install django-rest-framework

Go to your project setting.py and add rest_framework as an installed app.

[... ,
... ,
rest_framework,
... ,
]

now we will create a new script called serializer.py in our app folder.
Open and add the following code

from rest_framework import serializers
from .models import model_name


class mySerializer(serializers.ModelSerializer):
    class Meta:
        model = model_name
        fields = ['__all__']

Brace up 😁, you are almost done with your API.

Next up,
In views.py write the code below

from rest_framework.generics import ListCreateAPIView
from .serializer import mySerializer
from .models import model_name

class listApi(ListCreateAPIView):
    queryset = model_name.objects.all()
    serializer_class = mySerializer

Lastly we are going to assign a URL to our API
open urls.py

from django.urls import path
from .views import listApi

urlpatterns = [path('api/list', listApi.as_view),
]

open browser 127.0.0.1:8000

🎉🎉🎉

You just made a Class Based API view.

DEV Community: tobiadiks

How to update your database through django_rest_framework.

Writing an API in Django (Class Based)