Python While Loop: Display Odd and Even Jersey Numbers

Vinoth — Fri, 13 Nov 2026 06:54:48 +0000

In a school sports event, students wearing ODD jersey numbers enter the ground first. After they finish, students wearing EVEN jersey numbers enter the ground.

Let's use Python to display the order.

Displaying Odd Jersey Numbers

odd_no=1
print(odd_no,end=" ")
odd_no=odd_no+2
print(odd_no,end=" ")
odd_no=odd_no+2
print(odd_no,end=" ")
odd_no=odd_no+2
print(odd_no,end=" ")
odd_no=odd_no+2
print(odd_no,end=" ")
odd_no=odd_no+2

odd_no=1
while odd_no<=10:
print(odd_no,end=" ")
odd_no=odd_no+2

output 1 3 5 7 9

even_no=2
print(even_no,end=" ")
even_no=even_no+2
print(even_no,end=" ")
even_no=even_no+2
print(even_no,end=" ")
even_no=even_no+2
print(even_no,end=" ")
even_no=even_no+2
print(even_no,end=" ")
even_no=even_no+2

even_no=2
while even_no<=10:
print(even_no,end=" ")
even_no=even_no+2

output 2 4 6 8 10

combined program
print("Odd Jersey Numbers:")

odd_no=1
while odd_no<=10:
print(odd_no,end=" ")
odd_no=odd_no+2

print("\nEven Jersey Number:")

eeven_no=2
while even_no<=10:
print(even_no,end=" ")
even_no=even_no+2

Output:

Odd Jersey Numbers:
1 3 5 7 9

Even Jersey Number:
2 4 6 8 10

Python While Loop!

Vinoth — Fri, 13 Nov 2026 05:40:20 +0000

** Tenali Raman and the Palace Guards**

Tenali Raman wishes to meet the King. Before reaching the royal court, he has to pass through many palace gates. A guard is posted at each gate.

Every guard demands a share of whatever reward Tenali Raman receives from the King. Tenali Raman agrees and promises:

"I will give you half of whatever reward I receive from the King."

All the guards allow him to enter. After meeting the King, Tenali Raman receives a reward of 1024 lashes.

The interesting question is: How many guards can receive half of the remaining reward until the value becomes less than 1?

##Step 1: Manual Calculation

First, we can calculate the result manually.

python

guard = 0
received_lashes = 1024

guard = 1
received_lashes = received_lashes / 2

guard = 2
received_lashes = received_lashes / 2

guard = 3
received_lashes = received_lashes / 2

guard = 4
received_lashes = received_lashes / 2

guard = 5
received_lashes = received_lashes / 2

guard = 6
received_lashes = received_lashes / 2


This approach helps us understand the calculation at a basic level.

However, writing the same code repeatedly is not efficient. Also, we do not know how many guards there are.


## Step 2: Identifying the Repeated Pattern

We can see that two operations are repeated:

1. Divide `received_lashes` by `2`.
2. Increase the guard count by `1`.

For example:

#python
guard = guard + 1
received_lashes = received_lashes / 2

Since the same operations are repeated, we can use a while loop.

Step 3: Using a While Loop

guard = 0
received_lashes = 1024

while received_lashes >= 1:
    received_lashes = received_lashes / 2
    guard = guard + 1

print(received_lashes)
print(guard)
![ ](https://dev-to-uploads.s3.us-east-2.amazonaws.com/uploads/articles/x3tse2qigyuiqyeo9xpc.png)

Output
0.5
11

Explanation

The value is divided by 2 repeatedly:
1024 → 512 → 256 → 128 → 64 → 32 → 16 → 8 → 4 → 2 → 1 → 0.5
The loop runs 11 times.

Therefore:

Number of guards = 11
Remaining value = 0.5

Step 4: What Happens if We Start with `guard = 1`?

guard = 1
received_lashes = 1024

while received_lashes >= 1:
received_lashes = received_lashes / 2
guard = guard + 1

print(received_lashes)
print(guard)

Output
0.5
12

This happens because we started counting the guards from 1 instead of 0.
is the correct and clearer approach.

Correct Answer:

Guards counted: 11
Final remaining value: 0.5

DEV Community: Vinoth

Python While Loop: Display Odd and Even Jersey Numbers

Python While Loop!

python

Step 3: Using a While Loop

Step 4: What Happens if We Start with guard = 1?

Step 4: What Happens if We Start with `guard = 1`?