TypeScript - Check if an array contains only unique values

Intro

A cool trick in TypeScript is that you can use a Set to remove nonunique values from an array. Combine this with Array.from and you get a quick one liner to remove none unique values

const unqiueValues = Array.from(new Set(YOUR_ARRAY_HERE))

Step by step

// Our array of non unique values
const values = [0,0,1,'a','a','b','c'];

// Create a `Set` from our array
// Sets can only contain unique values so duplicate will be removed for us
const uniqueSet = new Set(values);

// Create a new array from our set so we can use the Array.length property
const unqiueValues = Array.from(uniqueSet);

// Compare the length of the original `values` array and the new `uniqueValues` array
// If the lengths differ then a non unique value was removed by the set
// This means that the original array contained non-unique values
const isUnique = (values.length === unqiueValues.length)

As a one liner

const values = [0,0,1,'a','a','b','c'];
const unique = (Array.from(new Set(values)).length === values.length);

As a function

onlyUnique(values: Array<any>): boolean {
  return (Array.from(new Set(values)).length === values.length);
}

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Comments

[Julien Barbay]

There's nothing of TS about this. Waste of time.

[RaulC-G]

another way:

function uniques (
item: T,
index: number,
array: any[]
) : T { return array.indexOf(item) == index); }

function everyIsUnique (array : any[]) : boolean {
return array.filter(uniques).length == array.length
}

[yossarian]

In order to use it, you shoul apply constraints for Array, because it can be only primitive values