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Daily Coding Challenge #45

wingkwong profile image Wing-Kam ・2 min read

Daily Coding Challenge (87 Part Series)

1) Daily Coding Challenge #1 2) Daily Coding Challenge #2 3 ... 85 3) Daily Coding Challenge #3 4) Daily Coding Challenge #4 5) Daily Coding Challenge #5 6) Daily Coding Challenge #6 7) Daily Coding Challenge #7 8) Daily Coding Challenge #8 9) Daily Coding Challenge #9 10) Daily Coding Challenge #10 11) Daily Coding Challenge #11 12) Daily Coding Challenge #12 13) Daily Coding Challenge #13 14) Daily Coding Challenge #14 15) Daily Coding Challenge #15 16) Daily Coding Challenge #16 17) Daily Coding Challenge #17 18) Daily Coding Challenge #18 19) Daily Coding Challenge #19 20) Daily Coding Challenge #20 21) Daily Coding Challenge #21 22) Daily Coding Challenge #22 23) Daily Coding Challenge #23 24) Daily Coding Challenge #24 25) Daily Coding Challenge #25 26) Daily Coding Challenge #26 27) Daily Coding Challenge #27 28) Daily Coding Challenge #28 29) Daily Coding Challenge #29 30) Daily Coding Challenge #30 31) Daily Coding Challenge #31 32) Daily Coding Challenge #32 33) Daily Coding Challenge #33 34) Daily Coding Challenge #34 35) Daily Coding Challenge #35 36) Daily Coding Challenge #36 37) Daily Coding Challenge #37 38) Daily Coding Challenge #38 39) Daily Coding Challenge #39 40) Daily Coding Challenge #40 41) Daily Coding Challenge #41 42) Daily Coding Challenge #42 43) Daily Coding Challenge #43 44) Daily Coding Challenge #44 45) Daily Coding Challenge #45 46) Daily Coding Challenge #46 47) Daily Coding Challenge #47 48) Daily Coding Challenge #48 49) Daily Coding Challenge #49 50) Daily Coding Challenge #50 51) Daily Coding Challenge #51 52) Daily Coding Challenge #52 53) Daily Coding Challenge #53 54) Daily Coding Challenge #54 55) Daily Coding Challenge #55 56) Daily Coding Challenge #56 57) Daily Coding Challenge #57 58) Daily Coding Challenge #58 59) Daily Coding Challenge #59 60) Daily Coding Challenge #60 61) Daily Coding Challenge #61 62) Daily Coding Challenge #62 63) Daily Coding Challenge #63 64) Daily Coding Challenge #64 65) Daily Coding Challenge #65 66) Daily Coding Challenge #66 67) Daily Coding Challenge #67 68) Daily Coding Challenge #68 69) Daily Coding Challenge #69 70) Daily Coding Challenge #70 71) Daily Coding Challenge #71 72) Daily Coding Challenge #72 73) Daily Coding Challenge #73 74) Daily Coding Challenge #74 75) Daily Coding Challenge #75 76) Daily Coding Challenge #76 77) Daily Coding Challenge #77 78) Daily Coding Challenge #78 79) Daily Coding Challenge #79 80) Daily Coding Challenge #80 81) Daily Coding Challenge #81 82) Daily Coding Challenge #82 83) Daily Coding Challenge #83 84) Daily Coding Challenge #84 85) Daily Coding Challenge #85 86) Daily Coding Challenge #86 87) Daily Coding Challenge #87

About

This is a series of Daily Coding Challenge. Each day I show a few solutions written in C++. The questions are from coding practice/contest sites such as HackerRank, LeetCode, Codeforces, Atcoder and etc.


/*
Sum Root to Leaf Numbers

Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path 1->2->3 which represents the number 123.

Find the total sum of all root-to-leaf numbers.

Note: A leaf is a node with no children.

Example:

Input: [1,2,3]
    1
   / \
  2   3
Output: 25
Explanation:
The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.
Therefore, sum = 12 + 13 = 25.
Example 2:

Input: [4,9,0,5,1]
    4
   / \
  9   0
 / \
5   1
Output: 1026
Explanation:
The root-to-leaf path 4->9->5 represents the number 495.
The root-to-leaf path 4->9->1 represents the number 491.
The root-to-leaf path 4->0 represents the number 40.
Therefore, sum = 495 + 491 + 40 = 1026.
*/

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    int solve(TreeNode *root, int sum){
        // recursive approach - add *10 for each layer and plus its value
        if(!root) return 0;
        if(!root->left&&!root->right) return sum*10+root->val;
        return solve(root->left, sum*10+root->val)+solve(root->right, sum*10+root->val);
    }
    int sumNumbers(TreeNode* root) {
        return solve(root,0);
    }
};

The source code is available in corresponding repo below. Star and watch for timely updates!

GitHub logo wingkwong / leetcode

🏆 A Collection of my LeetCode Solutions with Explanations 🏆

GitHub logo wingkwong / hackerrank

🏆 A Collection of my HackerRank Solutions with Explanations 🏆

GitHub logo wingkwong / codeforces

🏆 A Collection of my Codeforces Solutions with Explanations 🏆

GitHub logo wingkwong / atcoder

🏆 A Collection of my AtCoder Solutions with Explanations 🏆

Daily Coding Challenge (87 Part Series)

1) Daily Coding Challenge #1 2) Daily Coding Challenge #2 3 ... 85 3) Daily Coding Challenge #3 4) Daily Coding Challenge #4 5) Daily Coding Challenge #5 6) Daily Coding Challenge #6 7) Daily Coding Challenge #7 8) Daily Coding Challenge #8 9) Daily Coding Challenge #9 10) Daily Coding Challenge #10 11) Daily Coding Challenge #11 12) Daily Coding Challenge #12 13) Daily Coding Challenge #13 14) Daily Coding Challenge #14 15) Daily Coding Challenge #15 16) Daily Coding Challenge #16 17) Daily Coding Challenge #17 18) Daily Coding Challenge #18 19) Daily Coding Challenge #19 20) Daily Coding Challenge #20 21) Daily Coding Challenge #21 22) Daily Coding Challenge #22 23) Daily Coding Challenge #23 24) Daily Coding Challenge #24 25) Daily Coding Challenge #25 26) Daily Coding Challenge #26 27) Daily Coding Challenge #27 28) Daily Coding Challenge #28 29) Daily Coding Challenge #29 30) Daily Coding Challenge #30 31) Daily Coding Challenge #31 32) Daily Coding Challenge #32 33) Daily Coding Challenge #33 34) Daily Coding Challenge #34 35) Daily Coding Challenge #35 36) Daily Coding Challenge #36 37) Daily Coding Challenge #37 38) Daily Coding Challenge #38 39) Daily Coding Challenge #39 40) Daily Coding Challenge #40 41) Daily Coding Challenge #41 42) Daily Coding Challenge #42 43) Daily Coding Challenge #43 44) Daily Coding Challenge #44 45) Daily Coding Challenge #45 46) Daily Coding Challenge #46 47) Daily Coding Challenge #47 48) Daily Coding Challenge #48 49) Daily Coding Challenge #49 50) Daily Coding Challenge #50 51) Daily Coding Challenge #51 52) Daily Coding Challenge #52 53) Daily Coding Challenge #53 54) Daily Coding Challenge #54 55) Daily Coding Challenge #55 56) Daily Coding Challenge #56 57) Daily Coding Challenge #57 58) Daily Coding Challenge #58 59) Daily Coding Challenge #59 60) Daily Coding Challenge #60 61) Daily Coding Challenge #61 62) Daily Coding Challenge #62 63) Daily Coding Challenge #63 64) Daily Coding Challenge #64 65) Daily Coding Challenge #65 66) Daily Coding Challenge #66 67) Daily Coding Challenge #67 68) Daily Coding Challenge #68 69) Daily Coding Challenge #69 70) Daily Coding Challenge #70 71) Daily Coding Challenge #71 72) Daily Coding Challenge #72 73) Daily Coding Challenge #73 74) Daily Coding Challenge #74 75) Daily Coding Challenge #75 76) Daily Coding Challenge #76 77) Daily Coding Challenge #77 78) Daily Coding Challenge #78 79) Daily Coding Challenge #79 80) Daily Coding Challenge #80 81) Daily Coding Challenge #81 82) Daily Coding Challenge #82 83) Daily Coding Challenge #83 84) Daily Coding Challenge #84 85) Daily Coding Challenge #85 86) Daily Coding Challenge #86 87) Daily Coding Challenge #87

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wingkwong profile

Wing-Kam

@wingkwong

Consultant by day. Developer by night. AWS certified. Exploring #CloudNative currently.

Discussion

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hello ;)
if it were an array you can do it like this .. oh yes i didnt compile so figure to fix code .. remember nothing complete.. happy coding

int A[] = {4,9,0,5,1};
int len = sizeof(A)/sizeof(A*); // length
int i=0; int L=0;

while(i<len-3)
{
L = ((i+1)*2)-1;

if (L<len-3) A[L++]+=A[i]*10;
if (L<len-3) A[L]+=A[i++]*10;
}
L=0;
while(len-i) L+=A[i]+A[i++ +1];