Waves of probability increase reliability. Priority of Russia

Waves of probability increase reliability. Priority of Russia

Theory and Practice "0 and 1"

Mathematical laws are valid in all probabilities and it
is important to know a dozen of mismatch limits in a row.

Investigating logarithm is obtained:
formula including logarithm follows from calculation
probabilities of guessing consecutive events

For example, simplest: 0.7*0.7*0.7 = 0.7^3 = 0.343
degree to which it is necessary to build 0.7 to get 0.343
N = LOG(0.343)/LOG(0.7) = 3
and corresponding formula for not guessing

Multiplication of constant probabilities C+p^N=1
and in 20th century formula was restored by
Andrey Danilin: N = LOG(1-C)/LOG(1-p)
C — probability of winning guaranteed
p — probability of winning event.

Example task: number of mismatches in a row
with a probability of 99% for a probability of 48.65%
= LOG(1-0,99)/LOG(1-0,4865) = 7
and that means about 50% probability
easy to guess 7 times in a row

Easily possible to count:
formula was discovered by Andrey Danilin: N=7+(5*(1/x-2))
and for example, x=0.1 N=47 is normal and x=0.78 N=4 is normal.

same formulas are valid for probabilities above 50%.

Geometric progression contained in condition or in solution
meaning of “degree to which it is necessary to build”
is solved through logarithm

• Start

Using mismatch limit in a row in tables
a wave or a period of guessing of 2 types is detected:

1st type: wave or period — as probability itself
through number of runs and where probability is 1/3
there is a wave or guessing period after 3 runs;

2nd type: wave or period — as limit of discrepancies in a row
and where probability is 1/3 there is a wave or guessing period
in 12 draws and possibly several bets on signal

• Rates

Virtually raise stakes when you lose
and lower stakes when winning to minimum bet

Really set only observing Quadrat Economy Danilins

• Practice

We synthesize 50 numbers 0 and 1 controlling amount of 25

case: 00111000000011111101010011111000001010111010000111
specially assigned 7 consecutive losses 0000000

we get 4 results of form:
assumed a win / loss and guessed / failed to guess:

A — guess win — 1-1 — participation and win
E — guess loss — 0-0 — non-participation
I — not won — 0-1 — non-participation
U — loosing — 1-0 — participation and loss

• Practice: 001

idea: missing a few ex
and missed only former would be winning

notation: "!" = signal and "." = waiting

case: 00111000000011111101010011111000001010111010000111
code: ..!A........!A..........!A........!U...........!A.

isolate codes A&U = AAAUA = advantageous: A>U
no rate increase and 2 consecutive bids possible
after signal and loss and stop when winning

• Practice: 1st wave

comparable to perfect distribution

idea: 01010101010101010101010101010101010101010101010101
case: 00111000000011111101010011111000001010111010000111
code: EUIAIUEUEUEUEAIAIAEAEAEUIAIAIUEUEUIUIUIAIUIUEUEAIA

isolate codes A&U = UUUUUAAAAAUAAUUUUUAUUUA

see 5 losses in a row and balance is intact
because according to simplest system of betting on losing
7 consecutive losses are required until balance is reset
starting with minimum rate of 1%: = 2^7 = 128 percent of balance

ideas are completely identical signs will repeat
picture of coincidence with same number of mismatches in a row

idea: 00110011001100110011001100110011001100110011001101
case: 00111000000011111101010011111000001010111010000111
code: EEAAIEUUEEUUIIAAIIUAEIUUIIAAIEUUEEAUIEAAIEAUEEUAIA

isolate codes A&U = AAUUUUAAUAUUAUAUUAUAAAUUAA
see 5 consecutive losses and balance is intact

• Practice: 2nd wave

notation: "!" = signal and "." = waiting

idea: skip 7 consecutive as 0000000
and put a maximum of 2 in a row or before winning

case: 00111000000011111101010011111000001010111010000111
code: ...........!A.....................................

in example there could be a loss and see 1 win rare
therefore it is important to monitor all signs

Idea: simply skip 4 in a row like 0000
and put a maximum of 2 in a row or before winning
same formula including logarithm and reliability below

case: 00111000000011111101010011111000001010111010000111
code: ........!U......................!UA...........!A..

isolate codes A&U = UUAA
see 3 consecutive losses and balance is intact
but skipping 3 in a row as 000 would be more risk

• Practice: 2nd waves

matches on 2nd wave from previous match
we add a step as a calculated limit of mismatches in a row

notation: "!" = signal and "." = waiting

case: 00111000000011111101010011111000001010111010000111
code: ...123456!U......123456!A...123456!U..............
code: ....123456!U......123456!A...123456!A.............
code: .....123456!A.......123456!A.......123456!A.......
code: .............123456!U.123456!U.......123456!U.....
code: ..............123456!A...123456!U......123456!U...
code: ...............123456!U...123456!U......123456!A..
code: ................123456!U...123456!A..... 123456!A.

isolate codes A&U = UUAUAUUAAAUUUAAUAUUAA
see 3 consecutive losses and balance is intact

• Practice: 2 waves and more waves

idea 001: missing some ex would be losing
and missed only former would be winning

notation: "!" = signal and "." = waiting

case1: 00111000000011111101010011111000001010111010000111
code1: ..!U........!A..........!A........!U...........!A.

case2: 11100001011101010000011111001010111111000000011100
code2: .......!U...........!A......!U...............!A...

where case2 is reverse sequence from case1 for experiment

isolate codes A&U = UUAAAUUAA = advantageous: A>U
no rate increase and 2 consecutive bids possible
after signal and loss and stop when winning

see 2 consecutive losses and balance is intact

let us assume that all possible situations are independent:

case3: 0001000010000110000011
code3: ...!U...!U...!A.....!A

case4: 0001000011000100000011
code4: ...!U...!A...!U.....!A

at same time: UU / UA / AU / AA
so were: 1 win and 1 loss and 2 return

probability of winning 1/4 = 25 %
probability of losing 1/4 = 25 %
probability of return 1/2 = 50 %

everything with target: division not coincidence in row
and also same for 3 or more independent signs
and for ideas about a step over limit of mismatch in a row

• Conclusion

Waves of probability increase reliability

Nobel Prize will not receive itself

Comments

[AndreyDanilin]

Checking in Wolframalpha: reliability win and lose
both probability of winning and losing create 4 combinations:
C+p^N=1… (1-C)+p^N=1… C+(1-p)^N=1… (1-C)+(1-p)^N=1

Everything is interchangeable:
C=1-c… c=1-C… P=1-p… p=1-P

Artificial intelligence of Wolframalpha knows logarithm:
solve C+(1-p)^N=1 for N

wolframalpha.com/input/?i=solve+C%2B%281-p%29%5EN%3D1+for+N

[AndreyDanilin]

1000 programs

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[AndreyDanilin]

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