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Discussion on: Need help with The Odin's Project, Rock Paper Scissors assignment ️

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badgamerbad profile image
Vipul Dessai • Edited

Well for the starters the function playerWeapon and selectedWeapons should return something, so that your vars can hold the value they return.

Why its returning "Tie" is because

undefined === undefined // true
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Tip: create local variable inside your function, do not take them as argument and modify them (this is mutation and its bad)

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taepal467 profile image
Chantae P.

Thank you so much for your help. But thankfully I actually figured it out myself. The only thing is, now I have a new problem lol. Now I need to figure out how to show the scores and increment it when either player wins🤔

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qavsdev profile image
QAvsDEV

In JavaScript, there is a concept of truthy and falsy values. When used in place of booleans, all values except for false, 0, "" (empty string), null, undefined, and NaN will evaluate as true, because they are considered truthy.

In your code

if (playerWin) {
  playerScoreCount++;
}
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the playerWin variable always evaluates to true because you've defined it as "You Win!", which is a non-empty string, which in turn is truthy. Same goes for the computerWin variable.

You should have boolean variables which are reset to false each round, and then one of them is set to true in the if-blocks, where you compare the inputs to determine who wins.

As to how to show the score, do it in the same way as you update the weapons each round.

Hope this helps!

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taepal467 profile image
Chantae P.

Thank you for the help. But I've finally figured it out myself. Here is the solution I came up with:

 if (computerSelection === "📜" && playerSelection === "🪨") {
        computerScoreCount ++;
        computerScore.textContent = computerScoreCount;
        console.log("computer score: ", computerScoreCount);
        console.log("Computer Wins!");
      } else if (playerSelection === "📜" && computerSelection === "🪨") {
        playerScoreCount ++;
        playerScore.textContent = playerScoreCount;
        console.log("player score: ", playerScoreCount);
        console.log("You Win!");
      }

      if (computerSelection === "✂" && playerSelection === "📜") {
        computerScoreCount ++;
        computerScore.textContent = computerScoreCount;
        console.log("computer score: ", computerScoreCount);
        console.log("Computer Wins!");
      } else if (playerSelection === "✂" && computerSelection === "📜") {
        playerScoreCount ++;
        playerScore.textContent = playerScoreCount;
        console.log("player score: ", playerScoreCount);
        console.log("You Win!");
      }

      if (computerSelection === "🪨" && playerSelection === "✂") {
        computerScoreCount ++;
        computerScore.textContent = computerScoreCount;
        console.log("computer score: ", computerScoreCount);
        console.log("Computer Wins!");
      } else if (playerSelection === "🪨" && computerSelection === "✂") {
        playerScoreCount ++;
        playerScore.textContent = playerScoreCount;
        console.log("player score: ", playerScoreCount);
        console.log("You Win!");
      }

      if (computerSelection === playerSelection) {
          console.log("Tie!");
      } else if (playerScoreCount === 5) {
        console.log("Congratulations! You've Won!")
      } else if (computerScoreCount === 5) {
        console.log("Computer Wins. Play again?");
      }

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Eventually I will remove all the console.log's and clean up the code a bit, once I have everything working the way it should.

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qavsdev profile image
QAvsDEV

Yep, that's the way to do it - first get the code working, then clean it up (also known as refactoring).

When refactoring, consider incrementing the score and updating the UI in one place only. That way, if you need to change anything about the score logic or the HTML elements change, you'll need to change it once, instead of 6 times.

This may not be as important for this throwaway project, but it's a well-known software development principle called DRY (Don't Repeat Yourself). Eliminating duplicate code leads to a codebase which is more readable and much less error-prone.

Anyways, congrats on figuring it out and good luck with your next challenges!

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taepal467 profile image
Chantae P.

Thank you so much! I've finished my project and here's the end result

And yes I am very aware of DRY. I try to not have duplicate code.

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qavsdev profile image
QAvsDEV

Great job!

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taepal467 profile image
Chantae P.

Thanks!