const yesNoMaybe = (expressionA, expressionB, expressionC) => { if (expressionA) return 'yes'; if (expressionA && expressionB || expressionC) return 'nope'; return 'maybe'; } console.log(yesNoMaybe(expressionA, expressionB, expressionC));
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Discussion on: If (all) else is complicated, switch to switch?
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