That's if the user somehow gets access to the token and sends it with a request, which is very hard expect they're some hacker or something. And adding extra characters to the end of the token will make sure it's invalid and the verify token middleware checks for that.
The token is in the header "Authorization" right ? Any user can update the Authorization token in the request. Maybe it's not easy for everyone but it is possible.
JWT is encoded in base64, but in base64 you can add padding with "=" without changing the encoded message. "Hi dev.to !" in base64 is "SGkgZGV2LnRvICE=" but also "SGkgZGV2LnRvICE==" or "SGkgZGV2LnRvICE===".
So if you check the encoded token in the denylist you can just add "=" at the end of the token to bypass the denylist and use the token without changing the decoded value.
Here is the RFC for the base64: tools.ietf.org/html/rfc4648
That's if the user somehow gets access to the token and sends it with a request, which is very hard expect they're some hacker or something. And adding extra characters to the end of the token will make sure it's invalid and the verify token middleware checks for that.
If I didn't get you right, please explain.
The token is in the header "Authorization" right ? Any user can update the Authorization token in the request. Maybe it's not easy for everyone but it is possible.
JWT is encoded in base64, but in base64 you can add padding with "=" without changing the encoded message. "Hi dev.to !" in base64 is "SGkgZGV2LnRvICE=" but also "SGkgZGV2LnRvICE==" or "SGkgZGV2LnRvICE===".
So if you check the encoded token in the denylist you can just add "=" at the end of the token to bypass the denylist and use the token without changing the decoded value.
Here is the RFC for the base64: tools.ietf.org/html/rfc4648
Oh wow, didn't realize this. Thank you for sharing. Will check it out.