Discussion on: Can (aﾠ == 1 && a == 2 && ﾠa == 3) equal true?

[J. Pichardo]

Nice post, I wouldn't have thought about using an "invisible" character.

Now, for the curious people, there is also another way :)

const a = {
  valueOf: (function(){
      let x = 1;
      return () => x++;
    })()
}

console.log(a == 1 && a == 2 && a == 3); // => true

Just for reference, the concepts used here are type coercion, closures and immediate function invocation.

Regards

p.s. can a === 1 && a === 2 && a === 3 evaluate to true?

[Henrique Marques]

Nice! Way more useful and interesting than the actual post.

[Nested Software]

This is very cool and scary!

[Junyoung Clare Jang]

Yes, you also can make true from a === 1 && a === 2 && a === 3 without invisible character, since, we have getter.

let i = 0;
Object.defineProperty(window, 'a', {
  get: function() {
    return ++i;
  }
});
console.log(a === 1 && a === 2 && a === 3);

[J. Pichardo]

Precisely, nice catch.

[Karolis Ramanauskas]

Nice, interesting approach!