Not sure if I follow. O(n log n) is worst than O(n). Insertions in a binary tree are expensive to keep it balanced.
If you use a set or hashmap assuming zero collisions, the look up is O(1). Then the bottke neck is in the string iteration. Right?
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Not sure if I follow. O(n log n) is worst than O(n). Insertions in a binary tree are expensive to keep it balanced.
If you use a set or hashmap assuming zero collisions, the look up is O(1). Then the bottke neck is in the string iteration. Right?