Looks like you are solving it with JS. I would use a more functional style:
function countVowels(text) { const vowels = ['a', 'e', 'i', 'o', 'u']; return text .map(toLowerCase) .filter((c) => vowels.includes(c)) .length(); }
It looks better to me, though yours is perfectly valid.
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Looks like you are solving it with JS. I would use a more functional style:
It looks better to me, though yours is perfectly valid.