Discussion on: Daily Challenge #205 - Consonant String Value

[Vidit Sarkar]

C++ solution using simple for-loop

int solve(string s){
    int tempMax = 0, maxSoFar = 0;
    for(int i=0;i<s.length();i++){
        if(s[i] == 'a' || s[i] == 'e' || s[i] == 'i' || s[i] == 'o' || s[i] == 'u'){
            maxSoFar = max(tempMax, maxSoFar);
            tempMax = 0;
        }
        else{
            tempMax += s[i]-'a'+1;
        }
    }
    return max(maxSoFar, tempMax);
}