Because a is undefined.
The first a is scoped inside a function. You're printing the a that's outside and undefined.
So, a inside f lives inside the f, but it has nothing to do with the other a, they just share the same name
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Because a is undefined.
The first a is scoped inside a function. You're printing the a that's outside and undefined.
So, a inside f lives inside the f, but it has nothing to do with the other a, they just share the same name