Here is my solution a little bit different. Sacrifices memory in favor of speed, reversing a string in log(n) time complexity :)
log(n)
function reverseByDivide(input){ if(input.length < 2) return input var left = input.substring(0, input.length/2) var right = input.substring(input.length/2, input.length) return reverseByDivide(right) + reverseByDivide(left) }
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Here is my solution a little bit different. Sacrifices memory in favor of speed, reversing a string in
log(n)
time complexity :)