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My solutions in Haskell.
The first solution - inefficient(O(n) = n^3), yet very elegant looking:
O(n) = n^3
import Data.List (nub) solve :: Eq a => [[a]] -> Int solve = product . map (length . nub)
Slightly better solution (O(n) = n^2 * log n) using containers library:
O(n) = n^2 * log n
containers
import qualified Data.Set as Set solve :: Ord a => [[a]] -> Int solve = product . map (Set.size . Set.fromList)
And best solution (O(n) = n^2), but accepts only integers as input:
O(n) = n^2
import qualified Data.IntSet as Set solve :: [[Int]] -> Int solve = product . map (Set.size . Set.fromList)
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My solutions in Haskell.
The first solution - inefficient(
O(n) = n^3), yet very elegant looking:Slightly better solution (
O(n) = n^2 * log n) usingcontainerslibrary:And best solution (
O(n) = n^2), but accepts only integers as input: