Imagine we have one interface and these classes:
interface SuperType {
void test();
}
class DefaultSuperType implements SuperType{
@Ov...
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I think it's 1, and it's because the object is always of type
ChildOfSuperTypeno matter what type you store it in, so when the method is dispatched it will always resolve to the version onChildOfSuperType./me goes to check.
Spoiler here for anyone wondering what the answer is: repl.it/@samwho/KnownEnormousWeara...
1. It doesn't matter whethersuperTypeis cast asDefaultSuperType, because it's still aChildOfSuperType, and the function dispatch table will still point toChildOfSuperType.test().The others were right in saying
"1", but you also have the annotation wrong. It's just @OverrideThank you. I corrected it.
"1". Because, in Java, the actual object's implementation is used, and not the typecast.