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KenjiGoh
KenjiGoh

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Filter unique array members (remove duplicates)

METHOD 1 - Using filter:

indexOf will return the first index (position) that a specific value first appear in the array. By checking indexOf(item)=== index, we can get the unique values.

let array = ["πŸ‘", "😁", "πŸ‘", "πŸ‘", "😁", "😁"];
const filterArr = array.filter((item, index) => array.indexOf(item) === index);
console.log(filterArr); //[ 'πŸ‘', '😁' ]
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Instead of checking for duplicates using array.filter() method, we can make use of the Set Data Structure that by definition only allows unique values.

METHOD 2 - Using Set:

const unique = (arr) => {
  const nameSet = new Set();
  for (let i = 0; i < arr.length; i++) {
    nameSet.add(arr[i]); //add element to Set
  }
  Array.from(nameSet)
};
console.log(unique(values)); //[ 'πŸ‘', '😁' ]
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Shorter Method

const unique = (arr) => {
   return Array.from(new Set(arr));
}
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Set with Array Destructuring

const unique = (arr) => {
   return [...new Set(arr];
}
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METHOD 3 - Using Reduce:

const uniqueVal = array.reduce((unique, item) =>
  unique.includes(item) ? unique : [...unique, item]
);

console.log(uniqueVal); //[ 'πŸ‘', '😁' ]
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