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Even shorter
word.split('').reverse().join('')==word
This wouldn't work for "Arara" would it? It'd need some sort of case normalisation.
Also, what about "Taco cat".
The issuer of the challenge, David, said: "Lets keep it simple: only checking for words. No handling for spaces, punctuation or numbers."
But if we're handling capitals and spaces, how about:
let p=s=>(t=>[...t].reverse().join("")==t)(s.toLowerCase().replace(/\s/g,""))
Here,
p("Taco cat") //returns true, p("Arara") //returns true
Another slight mod and we can ignore all non-letter chars (numbers, punctuation, etc.):
let p=s=>(t=>[...t].reverse().join("")==t)(s.toLowerCase().replace(/[^A-z]/g,"")) p("A man, a plan, a canal: Panama.") // returns true
Even shorter
This wouldn't work for "Arara" would it? It'd need some sort of case normalisation.
Also, what about "Taco cat".
The issuer of the challenge, David, said:
"Lets keep it simple: only checking for words. No handling for spaces, punctuation or numbers."
But if we're handling capitals and spaces, how about:
Here,
Another slight mod and we can ignore all non-letter chars (numbers, punctuation, etc.):