Discussion on: The easiest problem you cannot solve.

[Ian Laird]

I didn't see this one in the comments

K(cat && dog)();
K()(cat)||dog;

And arrays are fun

K.call(null, [cat, dog].reverse()[0])();
K.apply(null, [cat, dog].reverse())();
K([ ...cat, ...dog].slice(3).join(""))();

Technically i think this follows the rules.

K({ cat: dog })()

And if the does then this should work too

K(`${cat} ${dog}`)()

[JavaScript Joel]

Beautiful!