The easiest problem you cannot solve.
joelnet Oct 8
Given the following code:
const K = a => b => a const cat = 'cat' const dog = 'dog'
K like this will output
K(cat)(dog) //=> "cat"
How can you call
K to output
dog without swapping the order of
dog must appear exactly once.
The Given cannot be modified.
// INVALID: Cannot swap order! K(dog)(cat) // NO CHEATING: May only appear once. K.bind(null, dog)(cat)(dog)
I know of two ways to solve this problem. Surprise me with another!
I should have also specified no bind, call, or apply, but the solutions are just too interesting :)
K in the problem is the K combinator, part of the SKI combinator calculus.
Spoilers are in the comments! BEWARE!
Many great solutions have been posted below! A lot I never considered. Also some very creative loopholes around the rules I created ;)
Here's one solution that went undiscovered. It's base64 encoded to hide the "spoiler". But if you are curious you can decode it using your console's