πΉ Problem: 2749 Minimum Operations to Make the Integer Zero
Difficulty: #Medium
Tags: #Math, #BitManipulation, #Greedy
π Problem Summary
Youβre given two integers
num1
andnum2
. In one operation, you can subtractnum2 * k
fromnum1
. The goal is to find the smallest integerk
such that the result can be represented as the sum of exactlyk
powers of two (not necessarily distinct). If no suchk
exists, return -1.
π§ My Thought Process
Brute Force Idea:
Try all possiblek
values, computex = num1 - num2*k
, then check ifx
can be broken into exactlyk
powers of two.
But checking this naively for large numbers would be too slow.-
Optimized Strategy:
- After subtracting, we get
x = num1 - num2*k
. - For
x
to work:
- After subtracting, we get
1. `x β₯ k` (since the smallest way to split is all ones, requiring at least `k`).
2. `k β₯ popcount(x)` (since we need at least one summand for each set bit in binary).
-
The smallest valid
k
is the answer.-
Algorithm Used:
Math + Bit Manipulation (
bit_count
to check popcount condition).
-
Algorithm Used:
Math + Bit Manipulation (
βοΈ Code Implementation (Python)
class Solution:
def makeTheIntegerZero(self, num1: int, num2: int) -> int:
k = 1
while True:
x = num1 - num2 * k
if x < k: # impossible since we can't split into k parts
return -1
if k >= x.bit_count(): # valid if k >= popcount(x)
return k
k += 1
β±οΈ Time & Space Complexity
- Time: O(num1 / num2) in worst case (looping k), but usually small because conditions fail quickly.
- Space: O(1).
π§© Key Takeaways
- β
Learned that
popcount(x)
gives the minimum number of summands (powers of two) needed to formx
. - π‘ The tricky part was realizing you also need
x β₯ k
to bound the maximum possible summands. - π Similar problems often combine math inequalities + binary representations.
π Reflection (Self-Check)
- [x] Could I solve this without help? (No, needed some guidance)
- [x] Did I write code from scratch?
- [x] Did I understand why it works?
- [x] Will I be able to recall this in a week? (Need to revisit binary condition intuition)
π Related Problems
- [[1658 Minimum Operations to Reduce X to Zero]]
- [[991 Broken Calculator]]
π Progress Tracker
Metric | Value |
---|---|
Day | 75 |
Total Problems Solved | 438 |
Confidence Today | π |
Leetcode Rating | 1530 |
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