πΉ Problem: 2749 Minimum Operations to Make the Integer Zero
Difficulty: #Medium
Tags: #Math, #BitManipulation, #Greedy
π Problem Summary
Youβre given two integers
num1andnum2. In one operation, you can subtractnum2 * kfromnum1. The goal is to find the smallest integerksuch that the result can be represented as the sum of exactlykpowers of two (not necessarily distinct). If no suchkexists, return -1.
π§ My Thought Process
Brute Force Idea:
Try all possiblekvalues, computex = num1 - num2*k, then check ifxcan be broken into exactlykpowers of two.
But checking this naively for large numbers would be too slow.-
Optimized Strategy:
- After subtracting, we get
x = num1 - num2*k. - For
xto work:
- After subtracting, we get
1. `x β₯ k` (since the smallest way to split is all ones, requiring at least `k`).
2. `k β₯ popcount(x)` (since we need at least one summand for each set bit in binary).
-
The smallest valid
kis the answer.-
Algorithm Used:
Math + Bit Manipulation (
bit_countto check popcount condition).
-
Algorithm Used:
Math + Bit Manipulation (
βοΈ Code Implementation (Python)
class Solution:
def makeTheIntegerZero(self, num1: int, num2: int) -> int:
k = 1
while True:
x = num1 - num2 * k
if x < k: # impossible since we can't split into k parts
return -1
if k >= x.bit_count(): # valid if k >= popcount(x)
return k
k += 1
β±οΈ Time & Space Complexity
- Time: O(num1 / num2) in worst case (looping k), but usually small because conditions fail quickly.
- Space: O(1).
π§© Key Takeaways
- β
Learned that
popcount(x)gives the minimum number of summands (powers of two) needed to formx. - π‘ The tricky part was realizing you also need
x β₯ kto bound the maximum possible summands. - π Similar problems often combine math inequalities + binary representations.
π Reflection (Self-Check)
- [x] Could I solve this without help? (No, needed some guidance)
- [x] Did I write code from scratch?
- [x] Did I understand why it works?
- [x] Will I be able to recall this in a week? (Need to revisit binary condition intuition)
π Related Problems
- [[1658 Minimum Operations to Reduce X to Zero]]
- [[991 Broken Calculator]]
π Progress Tracker
| Metric | Value |
|---|---|
| Day | 75 |
| Total Problems Solved | 438 |
| Confidence Today | π |
| Leetcode Rating | 1530 |
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