Variable Shadowing In Rust – “Let” Is Immutable But Not Constant

The post Variable Shadowing In Rust – “Let” Is Immutable But Not Constant appeared first on Qvault.

Let’s take a look at some of the common pitfalls with the keywords let and mut . Then, we will learn how immutable != constant by using variable shadowing.

Getting started with Rust can be daunting. Rust is well-known for being a safe language. One of the ways in which Rust is safe is through type-safety. Rust is strongly typed and defaults to immutable values.

The “let” Keyword

The simplest way to create a new variable in Rust is by using the “let” keyword:

fn main() {
    let my_num = 5;
    println!("{}", my_num);
}

let introduces a new variable into the current scope. By default new variables are immutable, which means they can’t be reassigned. For example:

fn main() {
    let my_num = 5;
    my_num = 6;
    println!("{}", my_num);
}

fails to compile with the error: cannot assign twice to immutable variable

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In Rust the keyword "let" in Rust can confused devs coming from JavaScript. In JS "let" is used to declare mutable values. In Rust, "let" declares immutable values, which contributes to Rust being a safer language. #rustlang #rust

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Variable Shadowing – The Dark Side of “let”

As we can see above, Rust’s immutability offered by the let keyword allows the compiler to ensure that a given variable can’t be changed… kind of. The following does not fail to compile:

fn main() {
    let my_num = 5;
    let my_num = 6;
    println!("{}", my_num);
}

We are allowed to declare a new variable with the same name, even all in the same scope. This doesn’t mutate “my_num“, it creates a new variable with a new spot in memory. The name “my_num” now refers to the new variable, and the old variable is no longer accessible by its name.

Variable shadowing also works in an inner scope. In the outer scope it is in a way the original variable remains “unshadowed”:

fn main() {
    let my_num = 5;
    // start new scope
    {
        let my_num = 6;
        println!("{}", my_num);
    }  
    println!("{}", my_num);
}

prints:

6
5

Notice how the pointer to the new variable is completely different:

fn main() {
    let my_num = 5;
    println!("my_num pointer address: {:p}", &my_num);
    let my_num = 6;
    println!("my_num pointer address: {:p}", &my_num);
}

prints:

my_num pointer address: 0x7ffeee0ad6f4
my_num pointer address: 0x7ffeee0ad74c

I’m personally not yet a fan of variable shadowing. My first impression is that it ruins the absolute safety that could have been provided. That said, I’ve heard compelling arguments for why it should exist. Namely that creating a new variable with the same name is terribly convenient.

tl;dr: Even though variables declared with “let” are immutable, the name of the variable can easily point to an entirely new variable. Don’t count on it being a true constant.

Mut – A “Normal” Mutable Variable

Variables declared with “let” can optionally be declared mutable using the “mut” keyword:

fn main() {
    let mut my_num = 5;
    my_num = 6;
    println!("{}", my_num);
}

Prints 6

Mutable variables are just that – mutable. The value changes but the underlying address in memory is the same:

fn main() {
    let mut my_num = 5;
    println!("my_num pointer address: {:p}", &my_num);
    my_num = 6;
    println!("my_num pointer address: {:p}", &my_num);
}

prints:

my_num pointer address: 0x7ffee5d6e6fc
my_num pointer address: 0x7ffee5d6e6fc

There are other interesting keywords to explore as well like const and static, but we’ll save those for another article.

Thanks For Reading

Hit me up on twitter @wagslane if you have any questions or comments.

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The post Variable Shadowing In Rust – “Let” Is Immutable But Not Constant appeared first on Qvault.

Comments

[Oisín]

I'm also not really a fan of shadowing, and observed at least one serious bug in an Elixir codebase due to an accidental shadowing (Elixir also uses immutability by default).