Java math challenge

#challenge #java

What should be printed?

        int result = 0;
        result = result + (null != null ? 3 : 2);
        result += (1 & 2) == 1 ? 2 : 3;
        result += 1e5;
        result += 1e2;
        System.out.println(result);

Top comments (5)

Andrew (he/him) • Apr 11 '19

10106.0, I think. Because:

null != null == true
1 & 2 == 0

Ildarov • Apr 11 '19

No, you made a little mistake, null == null always true, therefore null != null should always be false.

Andrew (he/him) • Apr 11 '19

Ah! You're right. 100105, then. (I also mistakenly added a .0 and lost a power of 10.)

By the way, if you put java after the backticks on your code box, it applies Java syntax highlighting!

This:

will produce

System.out.println(1 + 2 == 3);

...while this:

will produce

System.out.println(1 + 2 == 3);

This works with JavaScript (js), Python (python), and lots of other languages, as well.

Ildarov • Apr 11 '19

Wow, thank you! I didn't know it.

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