IMO, you don't need $ for printOfAll, since
printOfAll (Cons x y) = putStrLn (show x) >> printAllOf y
is enough.
You're right; this is much cleaner. I'm going to go back and edit the post now.
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IMO, you don't need $ for printOfAll, since
is enough.
You're right; this is much cleaner. I'm going to go back and edit the post now.