Python solution:

def perform_operation(operations, number): if not operations: return number if operations["sign"] == "*": return operations["value"] * number if operations["sign"] == "+": return operations["value"] + number if operations["sign"] == "-": return number - operations["value"] if operations["sign"] == "/": return number // operations["value"] zero = lambda operations=None : perform_operation(operations, 0) one = lambda operations=None : perform_operation(operations, 1) two = lambda operations=None : perform_operation(operations, 2) three = lambda operations=None : perform_operation(operations, 3) four = lambda operations=None : perform_operation(operations, 4) five = lambda operations=None : perform_operation(operations, 5) six = lambda operations=None : perform_operation(operations, 6) seven = lambda operations=None : perform_operation(operations, 7) eight = lambda operations=None : perform_operation(operations, 8) nine = lambda operations=None : perform_operation(operations, 9) get_operation = lambda operation, num : {"sign": operation, "value": num} plus = lambda num : get_operation("+", num) minus = lambda num : get_operation("-", num) times = lambda num : get_operation("*", num) divided_by = lambda num : get_operation("/", num)

Though I prefer this one from the CodeWars solutions!

def zero(f = None): return 0 if not f else f(0) def one(f = None): return 1 if not f else f(1) def two(f = None): return 2 if not f else f(2) def three(f = None): return 3 if not f else f(3) def four(f = None): return 4 if not f else f(4) def five(f = None): return 5 if not f else f(5) def six(f = None): return 6 if not f else f(6) def seven(f = None): return 7 if not f else f(7) def eight(f = None): return 8 if not f else f(8) def nine(f = None): return 9 if not f else f(9) def plus(y): return lambda x: x+y def minus(y): return lambda x: x-y def times(y): return lambda x: x*y def divided_by(y): return lambda x: x/y

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## re: Daily Coding Puzzles - Oct 29th - Nov 2nd VIEW POST

TOP OF THREAD FULL DISCUSSIONPython solution:

Though I prefer this one from the CodeWars solutions!