but since calling map(x => x.id) already returns a function
Yes, that example works if map is returning a function, but I guess my read at that point in the article was that map wasn't returning a function.
map
it takes a function (fn) and then some datum (m2)3 it returns the datum as transformed by said function
In which case the example that follows that presupposes it's already a curried implementation was confusing.
...aaaaand I feel like an idiot. I totally see it now! We're still working with (fn, m) => ... and not fn => m => ..., so that doesn't make sense yet. I'll update ASAP. Thanks for your patience, and nice 👀!
(fn, m) => ...
fn => m => ...
Quick fix was to change it to:
const mapId = map.bind(null, x => x.id)
Thanks again.
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Yes, that example works if
mapis returning a function, but I guess my read at that point in the article was thatmapwasn't returning a function.In which case the example that follows that presupposes it's already a curried implementation was confusing.
...aaaaand I feel like an idiot. I totally see it now! We're still working with
(fn, m) => ...and notfn => m => ..., so that doesn't make sense yet. I'll update ASAP. Thanks for your patience, and nice 👀!Quick fix was to change it to:
Thanks again.