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Discussion on: Daily Coding Puzzles - Nov 4th - Nov 9th

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Replies for: Thursday Scramblies (5 KYU): Complete the function scramble(str1, str2) that returns true if a portion of str1 characters can be rearranged to m...

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Courtney • 
function scramble(str1, str2) {
 let letterHolder = {};
 for (let letter of str1) {
   if(letterHolder[letter]) letterHolder[letter]++;
   else letterHolder[letter] = 1;
 }
 for (let letter of str2) {
   if(!letterHolder[letter]) return false
   else letterHolder[letter]--;
 }
 return true;
}