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Super Kai (Kazuya Ito)
Super Kai (Kazuya Ito)

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Set & Frozenset functions in Python (6)

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*Memo:

  • My post explains set and frozenset functions (1).
  • My post explains set and frozenset functions (2).
  • My post explains set and frozenset functions (3).
  • My post explains set and frozenset functions (4).
  • My post explains set and frozenset functions (5).
  • My post explains set and frozenset functions (7).
  • My post explains a set (1).
  • My post explains a frozenset (1).

isdisjoint() can check if the set or frozenset and other don't have any common elements as shown below:

*Memo:

  • The 1st argument is other(Required-Type:Iterable):
    • Don't use other=.

<Set>:

A = {10, 20, 30}        # set
B = frozenset([40, 50]) # frozenset
C = [30, 40]            # list

print(A.isdisjoint(B)) # True
print(A.isdisjoint(C)) # False
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<Frozenset>:

A = frozenset([10, 20, 30]) # frozenset
B = {40, 50}                # set
C = [30, 40]                # list

print(A.isdisjoint(B)) # True
print(A.isdisjoint(C)) # False
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issubset() can check if every element in the set or frozenset is in other as shown below:

*Memo:

  • The 1st argument is other(Required-Type:Iterable):
    • Don't use other=.
  • <= can do issubset(), supporting set and frozenset.

<Set>:

A = {10, 20, 30}                # set
B = frozenset([10, 20, 30, 40]) # frozenset
C = [10, 20, 30]                # list
D = (10, 20)                    # tuple

print(A.issubset(B)) # True
print(A.issubset(C)) # True
print(A.issubset(D)) # False
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A = {10, 20, 30}                # set
B = frozenset([10, 20, 30, 40]) # frozenset
C = frozenset([10, 20, 30])     # frozenset
D = frozenset([10, 20])         # frozenset

print(A <= B) # True
print(A <= C) # True
print(A <= D) # False
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<Frozenset>:

A = frozenset([10, 20, 30]) # frozenset
B = {10, 20, 30, 40}        # set
C = [10, 20, 30]            # list
D = (10, 20)                # tuple

print(A.issubset(B)) # True
print(A.issubset(C)) # True
print(A.issubset(D)) # False
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A = frozenset([10, 20, 30]) # frozenset
B = {10, 20, 30, 40}        # set
C = {10, 20, 30}            # frozenset
D = {10, 20}                # frozenset

print(A <= B) # True
print(A <= C) # True
print(A <= D) # False
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issuperset() can check if every element in other is in the set or frozenset as shown below:

*Memo:

  • The 1st argument is other(Optional-Type:Iterable):
    • Don't use other=.
  • >= can do issuperset(), supporting set and frozenset.

<Set>:

A = {10, 20, 30}                # set
B = frozenset([10, 20, 30, 40]) # frozenset
C = [10, 20, 30]                # list
D = (10, 20)                    # tuple

print(A.issuperset(B)) # False
print(A.issuperset(C)) # True
print(A.issuperset(D)) # True
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A = {10, 20, 30}                # set
B = frozenset([10, 20, 30, 40]) # frozenset
C = frozenset([10, 20, 30])     # frozenset
D = frozenset([10, 20])         # frozenset

print(A >= B) # False
print(A >= C) # True
print(A >= D) # True
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<Frozenset>:

A = frozenset([10, 20, 30]) # frozenset
B = {10, 20, 30, 40}        # set
C = [10, 20, 30]            # list
D = (10, 20)                # tuple

print(A.issuperset(B)) # False
print(A.issuperset(C)) # True
print(A.issuperset(D)) # True
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A = frozenset([10, 20, 30]) # frozenset
B = {10, 20, 30, 40}        # set
C = {10, 20, 30}            # set
D = {10, 20}                # set

print(A >= B) # False
print(A >= C) # True
print(A >= D) # True
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