Go solution. Its a bit verbose as it does not have optional/default params.
package main import ( "fmt" "strings" ) type Node struct { val string left *Node right *Node } func (node *Node) serialize() string { if node == nil { return "#" } leftSide := node.left.serialize() rightSide := node.right.serialize() ret := fmt.Sprintf("%s->%s->%s", node.val, leftSide, rightSide) return ret } func deserialize(str string) Node { node, _ := deserailizeNodes(strings.Split(str, "->")) return node } func deserailizeNodes(nodes []string) (Node, []string) { if len(nodes) == 0 { return Node{"", nil, nil}, nil } nextNode := nodes[0] if nextNode == "#" { return Node{"", nil, nil}, nodes[1:] } left, rem := deserailizeNodes(nodes[1:]) right, _ := deserailizeNodes(rem) if left.val == "" && right.val == "" { return Node{nextNode, nil, nil}, nil } if left.val == "" { return Node{nextNode, nil, &right}, nil } if right.val == "" { return Node{nextNode, &left, nil}, nil } node := Node{val: nextNode, left: &left, right: &right} return node, nil } func main() { node := Node{"root", &Node{"left", &Node{"left.left", nil, nil}, nil}, &Node{"right", nil, nil}} fmt.Println(node.serialize()) // root->left->left.left->#->#->#->right->#-># n := deserialize(node.serialize()) fmt.Println(n.left.left.val == "left.left") // true }
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Go solution. Its a bit verbose as it does not have optional/default params.