you can replace filter().count() > 0 with any() (or all() and reversed predicate) and it will shortcircuit: exit as soon as you find first non 0 and non 1, thus making this whole walk through vector faster
filter().count() > 0
Thanks Shamir, it is a good improvement!
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you can replace
filter().count() > 0with any() (or all() and reversed predicate) and it will shortcircuit: exit as soon as you find first non 0 and non 1, thus making this whole walk through vector fasterThanks Shamir, it is a good improvement!