Return an array consisting of the largest number from each provided sub-array. For simplicity, the provided array will contain exactly 4 sub-arrays.
Remember, you can iterate through an array with a simple for loop, and access each member with array syntax arr[i].
My solution:
function largestOfFour(arr) {
for (i = 0; i < arr.length; i++) {
var largest = arr[i][0];
for (j = 0; j < arr[i].length; j++) {
if (arr[i][j] > largest) {
return arr[i][j];
}
}
}
Why do I need to have an empty bracket set for largestNumberArray, per your example? I'm not exactly clear on that part.
For further actions, you may consider blocking this person and/or reporting abuse
We're a place where coders share, stay up-to-date and grow their careers.
The problem:
Return an array consisting of the largest number from each provided sub-array. For simplicity, the provided array will contain exactly 4 sub-arrays.
Remember, you can iterate through an array with a simple for loop, and access each member with array syntax arr[i].
My solution:
function largestOfFour(arr) {
for (i = 0; i < arr.length; i++) {
var largest = arr[i][0];
for (j = 0; j < arr[i].length; j++) {
if (arr[i][j] > largest) {
return arr[i][j];
}
}
}
Why do I need to have an empty bracket set for largestNumberArray, per your example? I'm not exactly clear on that part.