Discussion on: JavaScript One-Liners That Make Me Excited

[Ben Sinclair]

// I'd like to see a minifier work that hard.
document.location.search.replace(/(^\?)/,'').split('&').reduce(function(o,n){n=n.split('=');o[n[0]]=n[1];return o},{});

// Challenge accepted.
location.search.substr(1).split('&').reduce((o,n)=>{n=n.split('=');o[n[0]]=n[1];return o},{});

I'm not a big Javascript person so I don't know what the difference is between window.location, document.location and just location (which I assume uses the global window context). I know substr works fine on an empty string, and I'm making the (heroically cavalier) assumption that query strings start with a ? in all browsers' implementations of location.search.

But both of these return something incorrect if there's no query string:

{"": undefined}

Oops. Well, we can do something about that:

(() => {let x=location.search.substr(1).split('&').reduce((o,n)=>{n=n.split('=');o[n[0]]=n[1];return o},{});delete x[""];return x})()

And now it's longer and even less maintainable, but hey :)

[Andrew Healey]

This is brilliant, Ben! 😄

[Alex Lohr]

I can probably do it in even less characters... let me try:

q={};document.location.search.replace(/([^?&=]+)=([^&]+)/g,(_,k,v)=>q[k]=v);q;

[齐翊]

Hey, that one could not accept empty value (eg:'?a=&b=1&c=')
try this instead:

//keys should not be empty, but value can
q={};location.search.replace(/([^?&=]+)=([^&]*)/g,(_,k,v)=>q[k]=v);q;