const$=(s,p=document)=>{if(/object HTML.*Element/.test(s.toString())){thrownewError('[utils/dom/$] Passed dom element instead of selector (string).');}returnArray.from(p.querySelectorAll(s))};exportdefault$;
I even export it as $ because i got so used to it ;-)))
I should note that it always returns an array, so no matter if it returns one element or multiple, you can still have one code to iterate matching elements. And if you need only one because you know there will be only one, [0] saves the day, just like in jquery unwrapping method.
I made a slight adjustment that will save you the trouble of having to add [0] to the array if there's really only one instance of that selector.
const$=(selector,context=document)=>{if(/object HTML.*Element/.test(selector.toString())){thrownewError('[utils/dom/$] Passed dom element instead of selector (string).');}if(context.querySelectorAll(selector).length>0){return[...context.querySelectorAll(selector)];}else{returncontext.querySelector(selector);}};
I had it in previous version, but i value having returned array much more than this. Because i often map, i can safely map over array of one element, but it would throw if i dont have it inside the array. Im huge advocate of that.
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This is how my utility looks like for that:
I even export it as
$
because i got so used to it ;-)))I should note that it always returns an array, so no matter if it returns one element or multiple, you can still have one code to iterate matching elements. And if you need only one because you know there will be only one,
[0]
saves the day, just like in jquery unwrapping method.That's pretty nifty!
I made a slight adjustment that will save you the trouble of having to add [0] to the array if there's really only one instance of that selector.
I had it in previous version, but i value having returned array much more than this. Because i often map, i can safely map over array of one element, but it would throw if i dont have it inside the array. Im huge advocate of that.