Discussion on: Daily Challenge #250 - Last Digit of a Large Number

[peter279k]

Here is the solution with Python:

def last_digit(n1, n2):

    if n2 == 0:
        return 1

    last_digits = []

    step = 1
    while True:
        number = pow(n1, step)
        step += 1
        last_digit = int(str(number)[-1])

        if last_digit in last_digits:
            break

        last_digits.append(last_digit)

    print(last_digits)
    last_digit_index = n2 % len(last_digits) - 1

    return last_digits[last_digit_index]