this is the shortest valid solution :
int output = 1; for (int i = 1; i <= n; i++) { if (i != 1) { output = output + 4 * (i - 1); } }
return output;
i tried both solution function solution(n) { return 2*n*(n-1) +1; //return n*2+(n-1)*2 }
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this is the shortest valid solution :
int output = 1;
for (int i = 1; i <= n; i++) {
if (i != 1) {
output = output + 4 * (i - 1);
}
}
i tried both solution
function solution(n) {
return 2*n*(n-1) +1;
//return n*2+(n-1)*2
}