Answer: It is applied to too many arguments; maybe you forgot a `;'

answer re: It is applied to too many arguments; maybe you forgot a `;'

Jun 11 '18

1

When parsing the code the parser advances until it hits l q. At this point there could be more arguments that should get applied to the function l. So the parser keeps going and the next thing it finds is the value print_int. Another argument to l. Which gives…

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