if (y > x){ x += (y-x)/2; y = 2*(y-x) x += x-y } else if (y < x){ y += (y-x)/2; x = 2*(y-x) y += x-y }
Probably not the best way ...
You might want to try it in a language of your choice. If it works, it's a very good first step. Then, you can think of optimizing it.
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if (y > x){
x += (y-x)/2;
y = 2*(y-x)
x += x-y
}
else if (y < x){
y += (y-x)/2;
x = 2*(y-x)
y += x-y
}
Probably not the best way ...
You might want to try it in a language of your choice. If it works, it's a very good first step. Then, you can think of optimizing it.