Given the

`root`

of a binary tree, calculate thevertical order traversalof the binary tree.For each node at position

`(row, col)`

, its left and right children will be at positions`(row + 1, col - 1)`

and`(row + 1, col + 1)`

respectively. The root of the tree is at`(0, 0)`

.The

vertical order traversalof a binary tree is a list of top-to-bottom orderings for each column index starting from the leftmost column and ending on the rightmost column. There may be multiple nodes in the same row and same column. In such a case, sort these nodes by their values.Return the

vertical order traversalof the binary tree.

**Example 1:**

```
Input: root = [3,9,20,null,null,15,7]
Output: [[9],[3,15],[20],[7]]
Explanation:
Column -1: Only node 9 is in this column.
Column 0: Nodes 3 and 15 are in this column in that order from top to bottom.
Column 1: Only node 20 is in this column.
Column 2: Only node 7 is in this column.
```

**Example 2:**

```
Input: root = [1,2,3,4,5,6,7]
Output: [[4],[2],[1,5,6],[3],[7]]
Explanation:
Column -2: Only node 4 is in this column.
Column -1: Only node 2 is in this column.
Column 0: Nodes 1, 5, and 6 are in this column.
1 is at the top, so it comes first.
5 and 6 are at the same position (2, 0), so we order them by their value, 5 before 6.
Column 1: Only node 3 is in this column.
Column 2: Only node 7 is in this column.
```

**Example 3:**

```
Input: root = [1,2,3,4,6,5,7]
Output: [[4],[2],[1,5,6],[3],[7]]
Explanation:
This case is the exact same as example 2, but with nodes 5 and 6 swapped.
Note that the solution remains the same since 5 and 6 are in the same location and should be ordered by their values.
```

## Solution

```
from collections import deque, OrderedDict
from typing import List
from .util import TreeNode
class TravesalItem:
def __init__(self, node, row, col):
self.node = node
self.row = row
self.col = col
class Solution:
def verticalTraversal(self, root: TreeNode) -> List[List[int]]:
grid_items = []
traversal = {}
traversal_queue = deque([TravesalItem(root, 0, 0)])
while traversal_queue:
ti = traversal_queue.popleft()
if ti.node is not None:
grid_items.append((ti.col, ti.row, ti.node.val))
traversal_queue.append(
TravesalItem(ti.node.left, ti.row + 1, ti.col - 1)
)
traversal_queue.append(
TravesalItem(ti.node.right, ti.row + 1, ti.col + 1)
)
for col, row, val in sorted(grid_items):
if col not in traversal:
traversal[col] = []
traversal[col].append(val)
return traversal.values()
```

## Discussion (0)