Perfect NFL seasons are rare, but how rare should they be if you only know the per-game win probability? A binomial model gives a surprisingly clear answer.
One team
If a team wins each game independently with probability p, the chance it wins all 17 is p^17:
| p per game | P(17-0) |
|---|---|
| 0.80 | 2.3% |
| 0.85 | 6.3% |
| 0.90 | 16.7% |
| 0.95 | 41.8% |
A whole league
Now take a league of 32 teams. If the average team is a 50% favorite each week, the chance any specific team goes 17-0 is 0.5^17, about 0.0008%, or 1 in 131,072. Across 32 teams the chance that at least one is perfect by pure luck is about 32 / 131,072, roughly 0.024%, or about once in 4,100 seasons.
Real leagues are not made of coin flips, of course: a few teams are much stronger than average, which is why perfect seasons occasionally happen. But the model shows why they are so exceptional: you need a team that is a heavy favorite every week, not just most weeks.
Try it yourself
def p_perfect(p, games=17):
return p ** games
for p in (0.80, 0.85, 0.90, 0.95):
print(p, round(p_perfect(p) * 100, 1))
If you would rather draft a roster and simulate the season than do the arithmetic, 17-0 Game is a free browser sim built around exactly this question.
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