re: Daily Challenge #18 - Triple Trouble VIEW POST

re: JavaScript const tripleTrouble = (num1, num2) => { const min = Math.min(num1, num2); const strNum1 = num1.toString(); const strNum2 = n...

Hmmm.... reading other answers I might have misinterpreted what was required in this challenge. What is it exactly? For example, if num1 = 121 and num2 = 141, would they be triple troubled numbers? (because 7*3 = 21, and 7*2 =14) Or would it be num1 = 8777and num2 = 877 be triple troubled numbers? (because 7 repeats 3 times in the first one and 2 in the second one)


I'm getting caught up a few days behind, but I understood this is three digits in a row. Which I think is confirmed by the linked challenge examples.

So num1 = 8777 and num2 = 877 would return true for this!

Starting on my version now

To achieve that, the only change would be in the if statement. Instead of doing x*3 and x*2, it would be ''+x+x+x and ''+x+x respectively:

if (strNum1.indexOf(''+x+x+x) > -1 && strNum2.indexOf(''+x+x) > -1) {
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