Haskell!
import Data.Maybe diamond :: Int -> Maybe [Char] diamond n | n < 1 = Nothing | even n = Nothing | otherwise = Just (concat $ map line rows) where line stars = replicate (div (n - stars) 2) ' ' ++ replicate stars '*' ++ "\n" rows = filter odd ([1..n] ++ reverse [1..(n - 2)])
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Haskell!