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# Discussion on: Javascript Algorithms #1: Counting the Vowels in a String Of Text

Boian Ivanov • Edited on

A really good article for explaining algorithms through JavaScript for beginners. Good job and keep it up.

I thought though to try and add one more way of doing it, and that's recursively.
So here is my method for recursively finding the amount of vowels (feel free to use it).

``````const vowels = ["a", "e", "i", "o", "u"]

var count = 0;

function countVowelsRecursive(text) {
if(vowels.includes(text[0].toLowerCase())) {
count++;
}
if(text.length == 1){
console.log(`The text contains \${count} vowel(s)`);
return count;
} else {
countVowelsRecursive(text.substr(1));
}
}

countVowelsRecursive('I am a world-class developer using iterations');
``````

The two important places are :

• `text[0]` - gives us the first character of a string, because a string could be compared to an array of chars, and
• `text.substr(1)` - removes the first character of the string, while it gives it to the method.

After those two, if we're left with only one character the method gives us the result and returns the counter.

Philip Obosi

Awesome work Boain. Did you test the performance implications?

Boian Ivanov

I haven't tried, because I made it in like 10 minutes. But I presume it's could be close to yours. If you willing to test, do post the results here for future reference. I would be really interested to know.

Dimitris Klouvas

It may be a correct algorithm but the implementation is not a very good one. The `countVowelsRecursive` should be a pure function and not depend to scoped `count` variable. What happens when we run the `countVowelsRecursive` twice in the same code snippet? Is the result of the 1st call the same as the 2nd?

Boian Ivanov

No worries, you can make it a function in a function with the parent one having the count = 0 and then the child one doing the iteration. Though you got the point that the idea behind it was to showcase different algorithms, right ?