Well, the min() and max() method cannot take an array as an input, so spreading it can solve that problem too... It saved me a lot of headaches.
array = [1, 2, 3, 4, 5];
var minimum = Math.min(...array);
var maximum = Math.max(...array);
Ah yes! that's a fantastic use case! let me add it to my notes, thanks for sharing 💪
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