```
class Solution {
public:
int maxValueAfterReverse(vector<int>& A) {
if (A.size() == 2) return abs(A[0] - A[1]);
int ans = 0, N = A.size(), maxGap = 0, low = max(A[0], A[1]), high = min(A[0], A[1]);
for (int i = 1; i < N; ++i) ans += abs(A[i] - A[i - 1]);
for (int i = 3; i < N; ++i) {
maxGap = max({ maxGap, high - max(A[i - 1], A[i]), min(A[i - 1], A[i]) - low });
high = max(high, min(A[i - 2], A[i - 1]));
low = min(low, max(A[i - 2], A[i - 1]));
}
maxGap *= 2;
for (int i = 0; i < N - 2; ++i) maxGap = max(maxGap, abs(A[N - 1] - A[i]) - abs(A[i + 1] - A[i]));
for (int i = 2; i < N; ++i) maxGap = max(maxGap, abs(A[0] - A[i]) - abs(A[i] - A[i - 1]));
return ans + maxGap;
}
};
```

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