Haskell
import Data.List (intercalate) pattern :: Int -> String pattern n = intercalate "\n" $ map concat $ take n rows where rows = [ map show $ replicate i i | i <- [1..] ]
You could use unlines instead of intercalate "\n" to join the lines. Also, it looks like you have to support decimals.
unlines
intercalate "\n"
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Haskell
You could use
unlinesinstead ofintercalate "\n"to join the lines. Also, it looks like you have to support decimals.