I have done a Ruby one, based on counting the number of even values in the first three elements of the array to switch the logic between finding the first even and the first odd element.
[
[2, 4, 0, 100, 4, 11, 2602, 36],
[160, 3, 1719, 19, 11, 13, -21],
[4, 8, 15, 16, 24, 42],
[16, 6, 40, 66, 68, 28]
].map do |array|
case array.first(3).select(&:even?).size
when 1
array.find(&:even?)
else
array.find(&:odd?)
end
end
=> [11, 160, 15, nil]
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I have done a Ruby one, based on counting the number of even values in the first three elements of the array to switch the logic between finding the first even and the first odd element.